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Svetlanka [38]
3 years ago
7

Loretta swam 3 laps in 12.09 seconds. If she swam these three laps equally as fast, how long did it take her to swim two laps

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

4.03 Seconds

Step-by-step explanation:

12.09 divided by 3 laps

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18 first-graders and 72 other students attended a school assembly. What percentage of the students at the assembly were first-gr
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Answer:20%

Step-by-step explanation:

You add 72 plus 18 and get 100 then you find what 100 divided by 5 is.

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what is the solution to the system of equations shien on the graph? A.(0,5) B.(-2,1) C.(0,-1) D.(1,-2)
VLD [36.1K]

Solution is where the lines intersect. It's  is (-2 , 1)

Answer is B.(-2,1)

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3 years ago
Martin would like to start training to run a Martin the first week he runs a total of 15 miles he would like to run 30% more mil
Mice21 [21]

Answer:

Third week = 23.35 miles

Step-by-step explanation:

First week total miles = 15 miles

he would like to run 30% more miles each week than the week before

Second week = 15 miles + (30% of 15 miles)

= 15 + (30% * 15)

= 15 + (0.3 * 15)

= 15 + 4.5

= 19.5 miles

Second week = 19.5 miles

Third week = 19.5 miles + (30% of 19.5 miles)

= 19.5 + (30% * 19.5)

= 19.5 + (0.3 * 19.5)

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3 years ago
Perform the following operations and write the answers in radical form.
strojnjashka [21]

Given:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

To find:

The simplified radical form.

Solution:

Part A: \sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}

\sqrt{98}=\sqrt{7^2 \times 2} =7 \sqrt{2}

\sqrt{18}=\sqrt{3^2 \times 2} =3 \sqrt{2}

Substitute these in the given expression.

\sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}=\sqrt{7}+\sqrt{3}+7\sqrt{ 2}-3\sqrt{ 2}

Add or subtract the coefficient of same radical.

                                    =\sqrt{7}+\sqrt{3}+(7-3)\sqrt{ 2}

                                    =\sqrt{7}+\sqrt{3}+4\sqrt{ 2}

Part B: 3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}

2 \sqrt{121}=2\sqrt{11^2}

           =2\times 11

           = 22

3 \sqrt{90}=3\sqrt{3^2 \times 10}

           =3\times 3 \sqrt{10}

           =9 \sqrt{10}

Substitute these in the given expression.

3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}=3 \sqrt{5}-3 \sqrt{11}+22-9 \sqrt{10}

8 0
3 years ago
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Answer:

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