2 years ago

2x + 7 ≥ x + x + 1 Please solve this and show all of your work!

1 answer:

7 0

Answer:

Step 1 : Equation at the end of step 1 : (2x - 1) • (x + 7) = 0 Step 2 : Theory - Roots of a product : 2.1 A product of several terms equals zero. When a product of two or more terms equals zero, then at least one of the terms must be zero. We shall now solve each term = 0 separately

Step-by-step explanation:

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Solve the quadratic. x^2+8x+3=0

Reil [10]

Factor
find wht 2 numbers add to 8 and multiply to 3
none do

use quadratic formula which can be used when
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}}-4ac }{2a}$

a=1
b=8
c=3

x= $\frac{-8+/- \sqrt{8^{2}-4(1)(3)} }{2(1)}$
x= $\frac{ -8+/- \sqrt{64-12} }{2}$
x= $\frac{ -8+/- \sqrt{52} }{2}$
x= $\frac{ -8+/- 2 \sqrt{13} }{2}$
x= $-4+/- \sqrt{13}$

x= $-4+ \sqrt{13}$ or x= $-4- \sqrt{13}$
aprox x=-7.60555 or x=-0.394449

6 0

2 years ago

Read 2 more answers

I need help im not sure how to do this

sleet_krkn [62]

Answer:

Step-by-step explanation:

x-1 = 0

x = 1

f(x) = 3x⁵+2x⁴+5

f(1) = 3(1)⁵+2(1)⁴+5

= 3+2+5