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4 years ago

You pull on a wagon resting on the sidewalk. What will happen next.

1 answer:

8 0

I believe it's C. The wagon does not move move because the force you apply to the wagon is equal to the force it applies to you. If the maximum friction force is greater than that force the wagon will not move.

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The resistance of a wire depends upon the material's resistivity and the length and cross‑sectional area of the wire. What will

andriy [413]

Answer:

R' = 4R

The resistance will become 4 times the initial value.

Explanation:

The resistance of a wire at room temperature, is given by the following formula:

R = ρL/A ----------- equation 1

where,

R = Resistance of wire

ρ = resistivity of the material

L = Length of wire

A = Cross-sectional area of wire

Now, if the length (L) is multiplied by 4, then resistance will become:

R' = ρ(4L)/A

R' = 4 (ρL/A)

using equation 1:

R' = 4R

The resistance will become 4 times the initial value.

6 0

4 years ago

If the current decreases uniformly from 5.00 a to 2.00 a in 3.00 ms, calculate the self-induced emf in the coil.

Shkiper50 [21]

If the current decreases uniformly from 5.00A to 2.00 A in 3.00ms , the self-induced emf in the coil. =70.02025 V

5 0

3 years ago

PLEASE ITS AN Emergency IF ITS RIGHT I WILL GIVE BRAINLIEST

Art [367]

Uh I think it’s point guard

3 0

3 years ago

The electric field between the plates of a parallel-plate capacitor is horizontal, uniform, and has a magnitude E. Asmall object

kirza4 [7]

Answer:

$m = 0.041 kg$

Explanation:

As we know that the small particle is in equilibrium at an angle of 16 degree with the vertical

so here we can use force balance in vertical and horizontal direction

$T cos\theta = mg$

$T sin\theta = qE$

now from above equation we have

$T = \sqrt{(mg)^2 + (qE)^2}$

also by division of above two equations we have

$\frac{qE}{mg} = tan\theta$

$qE = mg tan\theta$

now from above equation again

$T = \sqrt{(mg)^2 + (mg)^2 tan^2\theta}$

$T = mg sec\theta$

$0.420 = m(9.81) sec 16$

$m = 0.041 kg$

3 0

3 years ago

A 100-watt lightbulb radiates energy at a rate of 100 J/s. (The watt, a unit of power, or energy over time, is defined as 1 J/s.

fomenos

Answer:

$N=2.18\cdot 10^{20}photons/s$

Explanation:

The energy of a photon is: $E=h\nu=h\frac{c}{\lambda}$ when h is the Planck constant.

$h=6.63\cdot 10^{-34}Js$

$c=3.8\cdot 10^{8}m/s$

Then, we calculate the energy of a photon with a wavelength equal to 550 nm.

$E= 4.58\cdot 10^{-19}J$

To find the number of photons we can use this equation:

$N=\frac{P}{E}=\frac{100}{4.58\cdot 10^{-19}}=2.18\cdot 10^{20} photons/s$

Have a nice day!

7 0

3 years ago