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enot [183]
4 years ago
9

What is a possible explination for why the giant ice caps that covered a supercontinent in the paleozoic era melted?

Physics
2 answers:
natka813 [3]4 years ago
8 0

Answer:

Greenhouse effect

Explanation:

The Paleozoic era is followed by the Mesozoic era. The Mesozoic era consists of three periods Triassic, Jurassic, and Cretaceous.

During the cretaceous period the temperature of earth was 10 to 15 °C warmer than it is today. This warmth was caused due to the increase in volcanic activity of Earth. As the tectonic plates were moving this created mantle from the Earth's core rose to the surface causing increased volcanic activity. This volcanic activity increased the amount of CO₂ in the atmosphere thus creating the greenhouse effect.

Thepotemich [5.8K]4 years ago
6 0
The Paleozoic era spanned from the Cambrian to the Permian and ended with a mass extinction at the end of the Permian. Geologists are still unsure of the cause but the theories include a meteorite impact or a massive volcanic event in Siberia or a combination of both. This could be a possible cause of the melting of the late Paleozoic ice sheets. 
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A 2 kg object traveling at 5 m s on a frictionless horizontal surface collides head-on with and sticks to a 3 kg object initiall
Svetlanka [38]

Answer: (d)

Explanation:

Given

Mass of object m=2\ kg

Speed of object u=5\ m/s

Mass of object at rest M=3\ kg

Suppose after collision, speed is v

conserving momentum

\Rightarrow mu+0=(m+M)v\\\\\Rightarrow v=\dfrac{2\times 5}{2+3}\\\\\Rightarrow v=2\ m/s

Initial kinetic energy

k_1=\dfrac{1}{2}\times 2\times 5^2\\\\k_1=25\ J

Final kinetic energy

k_2=\dfrac{1}{2}\times (2+3)\times 2^2\\\\k_2=10\ J

So, it is clear there is decrease in kinetic energy . Thus, energy decreases and velocity becomes 2 m/s.

4 0
3 years ago
A crate with a mass of m = 450 kg rests on the horizontal deck of a ship. The coefficient of static friction between the crate a
Zielflug [23.3K]

Answer:F_{v} =\mu_{k} mg

Magnitude of the force is 2601.9 N

Explanation:

m = 450 kg

coefficient of static friction μs = 0.73

coefficient of kinetic friction is μk = 0.59

The force required to  start crate moving is F_{s} =\mu_{s} mg.

but once crate starts moving the force of friction is reduced  F_{v} =\mu_{k} mg.

Hence  to keep crate moving at constant velocity we have to reduce the  force pushing crate ie F_{v} =\mu_{k} mg.

Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as  forces are balanced.

Magnitude of the force

F_{v} =\mu_{k} mg\\F_{v} =0.59 \times 450 \times 9.8\\F_{v} =2601.9  N

4 0
3 years ago
after singing for a few minutes the soloist rejoins the choir a second choir, consist of 90 additional singers then joins in eac
vredina [299]
If the soloist produces "x" decibels and the 10-person choir produces "y" decibels, combined they will produce "x+y" decibels. 

The second choir has 90 additional singers, we base our description on the first choir. If a 10-person choir produces "x+y" decibels, then the 90 person choir produces 10 (x+y) decibels. 
7 0
3 years ago
Velocity is a vector quantity because...
statuscvo [17]
It has both magnitude and direction
5 0
3 years ago
A 10.0 kg weather rocket generates a thrust of 230 NN . The rocket, pointing upward, is clamped to the top of a vertical spring.
blondinia [14]

Answer: 0.2m

Explanation: Firstly only the Rocket's Weight Compress the spring which can be found by

F_r=M_r*g\\F_r=10*9.81\\F_r=98.1N

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F_r=k*x\\x=F_r/k\\x=98.1/480\\x=0.2m

The part b and c of this question is done in the attachment

7 0
3 years ago
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