Answer:
a) 83.33 rad/s^2
b) 2500 rad/s
c) 6187.5 rad
Explanation:
Given data:
radius of wheel = 20.0 cm
mass of wheel = 3.0 kg
force = 25 N
a) angular acceleration
we know torque is given as



solving for angular acceleration 

b) angular velocity
duartion of force applied = 30.0 sec

= o + 83.33 *30 = 2500 rad/sec
c) angular displacement




Answer:
Fk = 21.645N
Explanation:
Let Fb be Force of block and thus;
Fb= mg where m is mass of block and g is acceleration due to gravity
Thus Fb= 9kg x 9.81N/kg = 88.29 N
Now, the question says this force Fb rests at an inclined plane [email protected] 30° angle
Thus;
Force parallel to inclined plane = 88.29 x sin30° = 44.145 N.
Force perpendicular to the inclined plane = 88.29 x cos30 = 76.46 N
Now, when an object is falling freely, we know that
h = (1/2)at^(2)
From the question, the height is 5m and t= 2 seconds
Thus;
5 = (1/2)a(2)^(2)
2a = 5 and thus,
a = 5/2 = 2.5 m/s^(2)
Now, in inclined planes, perpendicular force - kinetic friction force = Resultant force
Thus let perpendicular be Fp and kinetic friction force be Fk and so;
Fp - Fk = F
F= ma = 9 x 2.5 = 22.5N
Thus, 44.145 - Fk = 22.5
Thus, Fk = 44.145 - 22.5 = 21.645N
The all minerals are pure and free from gangue particles......
Answer: A device that uses infrared sensors.
Explanation:
<u><em>Answer:</em></u>
The answer is 1400 J, according to my Physics teacher.
<u><em>Explanation:</em></u>
You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)