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Ira Lisetskai [31]
3 years ago
7

Figure 1 shows the kinetic energy as a function of time for a 2kg object that is released from rest and falls toward Earth’s sur

face. Figure 2 shows the kinetic energy as a function of time for a 5kg object that is released from rest and falls toward Earth’s surface. Both objects are released simultaneously from the same height. How much does the gravitational potential energy of the object-object-Earth system change from 0s to 10s ?
a) 400J
b)600 J
c)1000 J
d) 1400J
Physics
1 answer:
garri49 [273]3 years ago
7 0

<u><em>Answer:</em></u>

The answer is 1400 J, according to my Physics teacher.

<u><em>Explanation:</em></u>

You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)

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SpyIntel [72]
B.
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7 0
3 years ago
What is the equivalent resistance of the circuit?
Kaylis [27]

Answer:

80 Ω.

Explanation:

In this circuit the resistances are in series.The equivalent resistance of a series circuit is equal to the sum of the resistances. Req= 60 + 20 = 80 Ω.

8 0
3 years ago
At takeoff, a commercial jet has a speed of 72 m/s. Its tires have a diameter of 0.89 m. Part (a) At how many rev/min are the ti
34kurt

Answer:

a) Revolutions per minute = 2.33

b) Centripetal acceleration = 11649.44 m/s²

Explanation:

a) Angular velocity is the ratio of linear velocity and radius.

Here linear velocity = 72 m/s

Radius, r  = 0.89 x 0. 5 = 0.445 m

Angular velocity

         \omega =\frac{72}{0.445}=161.8rad/s

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Revolutions per minute = 2.33

b) Centripetal acceleration

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  Here linear velocity = 72 m/s

  Radius, r  = 0.445 m

Substituting

   a=\frac{72^2}{0.445}=11649.44m/s^2

Centripetal acceleration = 11649.44m/s²

6 0
2 years ago
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Aleksandr [31]

Answer:

The motion in which all particles of a body move through the same distance in the same time.

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6 0
3 years ago
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weeeeeb [17]

Answer:

t = 0.67 [s]

Explanation:

To solve this problem we must use the following kinematics equation.

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Now replacing in the equation we have:

20 = 10 + (15*t)

t = (20-10)/15

t = 0.67 [s]

7 0
3 years ago
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