solve the following compound inequality graph the solution 7x = 35 ? please help and also show ur work on how u got it

The bad debt ratio for a financial institution is defined to be the dollar values of loans defaulted divided by the total dollar

Nimfa-mama [501]

Answer:

(a) NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5%

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5%

(b) We conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Step-by-step explanation:

We are given that a random sample of seven Ohio banks is selected.The bad debt ratios for these banks are 7, 4, 6, 7, 5, 4, and 9%.The mean bad debt ratio for all federally insured banks is 3.5%.

We have to test the claim of Federal banking officials that the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

(a) Let, NULL HYPOTHESIS, $H_0$ : $\mu \leq$ 3.5% {means that the the mean bad debt ratio for Ohio banks is less than or equal to the mean for all federally insured banks}

ALTERNATE HYPOTHESIS, $H_1$ : $\mu$ > 3.5% {means that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks}

The test statistics that will be used here is One-sample t-test;

T.S. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean debt ratio of Ohio banks = 6%

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 1.83%

n = sample of banks = 7

So, test statistics = $\frac{6-3.5}{\frac{1.83}{\sqrt{7} } }$ ~ $t_6$

= 3.614

(b) Now, at 1% significance level t table gives critical value of 3.143. Since our test statistics is more than the critical value of t so we have sufficient evidence to reject null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the the mean bad debt ratio for Ohio banks is higher than the mean for all federally insured banks.

Hence, Federal banking officials claim was correct.

7 0

3 years ago

Find the missing factor 7s^2+25s+12=(s+3)()

Deffense [45]

$7s^2+25s+12=\\
7s^2+21s+4s+12=\\
7s(s+3)+4(s+3)=\\
(s+3)(7s+4)$

It's 7s+4.

8 0

3 years ago

Y = 5-3x, Darw the graph of the function. Use the find the value of y when x=4, and when x = 5

stellarik [79]

Answer:

The line passes through (4, -7) and (5, -10).

Step-by-step explanation:

When x = 4, y = 5 - 3(4), or 5 - 12, or -7. Thus the point (4, -7) lies on the graph. Similarly y = 5 - 3(5) = -10 when x = 5. Thus, the line also goes through (5, -10). Plot these two points and draw a line through them. Doing this will result in the desired graph.

6 0

2 years ago

The circumference of circle p is 800 mm, the circumference of circle q is 200 cm, and the circumference of circle r is 4 m. What

shepuryov [24]

Let us use the following conversions:

1 cm = 10 mm

1 meter = 100 cm = 1000 mm

Given:

p = 800 mm

q = 200 cm = 2000 mm

r= 4 m = 4000

X = sum of the distance around each circle

X = p+q+r

X = 800+2000+4000

7 0

3 years ago

A large industrial firm allows a discount on any invoice that is paid within 30 days. of all invoices, 10% receive the discount.

Daniel [21]

This situation has two outcomes: either an invoice is discounted or not. This two outcomes satisfy what we call a binomial distribution (note "bi" in binomial).

The binomial distribution tells us the probability that a randomly selected sample will have the outcome of success. In this case, we consider receiving the discount as the "success" outcome while not receiving it means "failure". The distribution takes the form:

$P(X=x)= _{n}C_{x} p^{x} q^{n-x}$
where n is the total number of samples, x is the number of samples you'll expect to have a success outcome, p is the probability of success, q is the probability of failure, and nCx is the combination of n samples taken x at a time.

You have an inconsistency regarding the total number of samples by the way, but I will take the first mentioned sample of 15 as I answer (you can just follow through the same process for another value).

For the next step, let's digest the problem to get the needed variables.

The total number of samples, n, is equal to 15. The probability of success (receiving a discount), p, is 10% or 0.1, and the probability of failure (not receiving a discount) is 90% or 0.9.

For P(X=x), we need to find the probability that less than two of the samples have success outcomes therefore we need to find the probability that NO invoice will receive the discount plus the probability that ONE invoice will receive the discount. This is equivalent to saying
$P(X\ \textless \ 2)=P(X=0)+P(X=1)$

Calculating these probabilities we'll get:
$P(X=0)= _{15}C_{0} (0.1)^{0} (0.9)^{15}=0.206$
$P(X=1)= _{15}C_{1} (0.1)^{1} (0.9)^{14}=0.343$
$P(X\ \textless \ 2)=P(X=0)+P(X=1)=0.206+0.343=0.549$

ANSWER: The probability that fewer than 2 sampled invoices will receive the discount is 0.549 or 54.9%.

6 0

3 years ago

solve the following compound inequality graph the solution 7x = 35 ? please help and also show ur work on how u got it ​

solve the following compound inequality graph the solution 7x = 35 ? please help and also show ur work on how u got it