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True [87]
3 years ago
11

Find the zeros of the function. f(x) = 3x^3 - 21x^2 + 36

Mathematics
1 answer:
Monica [59]3 years ago
3 0

Step-by-step explanation:

f(x)=3x3−21x2+36xf(x)=3x3-21x2+36x

Set 3x3−21x2+36x3x3-21x2+36x equal to 00.

3x3−21x2+36x=03x3-21x2+36x=0

by Solving for x

x=0,4,3

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I don’t remember how I get the answer to this. I have the answer key though. Please help, I have a test in an hour
mrs_skeptik [129]

Answer:

  f(x) = (x -2)(x -1+3i)(x -1-3i)

Step-by-step explanation:

You can use synthetic division to find the remaining quadratic factor in the cubic. Then any of the usual means of solving the quadratic will help you find its linear factors.

In the attached, I show the synthetic division, the factoring to real numbers, and the solution that finds the complex linear factors by completing the square.

Of course, you know that for zeros a, b, and c, the linear factors are ...

  f(x) = (x -a)(x -b)(x -c)

Here, we have a=2, b=1-3i, c=1+3i.

  f(x) = (x -2)(x -1+3i)(x -1-3i)

5 0
3 years ago
Read 2 more answers
Help me out please?<br>chapter : exponents and powers​
belka [17]

Answer:

\frac{125}{27}

Step-by-step explanation:

\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}

Lets expand all the composite numbers into prime numbers.

=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}

Lets cancel 2^{-4} from numerator and denominator.

=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}

Using laws of exponents , lets solve this.

=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}

=> \frac{3^{-3} \times 5^{1}}{5^{-2}}

=> 3^{-3} \times 5^{[1 - (-2)]}

=> 3^{-3} \times 5^{3}

=> \frac{5^3}{3^3} = \frac{125}{27}

4 0
3 years ago
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Find the value of x that satifies the equation sin (4x+14)° = cos (-3x + 73)°
daser333 [38]
The answer is b, x=3
8 0
3 years ago
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How many triangles will there be in the 7th term of the following sequence?
nikitadnepr [17]
The answer is number 3.
4 0
2 years ago
The coordinates of the midpoint of GH are M(-2, 0), and the coordinates of one endpoint are H(4,-4).
Svetlanka [38]

The coordinate of point S from the giving coordinate point is (-8,4)

<h3>Midpoint of coordinates</h3>

The formula for calculating the midpoint of coordinate point is expressed as:

M(x,y) = {(x₁+x₂)/2, (y₁+y₂)/2}

Determine the measure of the coordinate S
-2 = 4+x₂/2

2(-2) = 4+x₂

x₂ = -4-4

x₂ = -8

Similarly

0 = -4+y₂/2

0(2) = -4+y₂

y₂ = 4

Hence the coordinate of point S from the giving coordinate point is (-8,4)

Learn more on midpoint here: brainly.com/question/5566419

#SPJ1

4 0
1 year ago
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