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3 years ago

Tại sao dung dịch nacl dẫn điện

Chemistry

1 answer:

Margaret [11]3 years ago

6 0

Tai said dung such nacl dân dên
Gggggghgggggggggghgggga

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A food product contains 15 g of carbohydrates (CHO), 5 g of protein (PRO), and 4 g of fat. How many calories are in one serving

ANEK [815]

Answer:

116 Cal

Explanation:

15 g CHO × 4 Cal/g = 60 Cal

5 g PRO × 4 Cal/g = 20

4 g fat × 9 Cal/g = <u> 36 </u>

TOTAL = 116 Cal

There are 116 Cal in one serving of the product.

6 0

3 years ago

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What type of compound is this?

vichka [17]

Answer:sorry id ont known

Explanation:give m brianlest if you want

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3 years ago

Why do grazing animals still need to migrate?

Umnica [9.8K]

1. because eventually the grass/food they are eating will loose its nutrients from eating it all the time and they need to migrate to find better food

2. the weather

3. their predators may migrate to the place they are and they need to migrate in order to have a better chance of survival

hope this helps these are just some reasons just ask if you need anymore

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3 years ago

If you had excess aluminum, how many moles of aluminum chloride could be produced from 28.0 g of chlorine gas, Cl2?

Mice21 [21]

Answer:

Yes chemistry. Try to add then multiply the top. Get the moles and you will find it.

Explanation:

Try to add then multiply the moles in the equation

6 0

4 years ago

Calculate the fractional saturation for hemoglobin when the partial pressure of oxygen is 40 mm Hg. Assume hemoglobin is 50%% sa

kumpel [21]

Answer:

The fractional saturation for hemoglobin is 0.86

Explanation:

The fractional saturation for hemoglobin can be calculated using the formula

$Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }$

Where $Y_{O_{2} } \\$ is the fractional oxygen saturation

${P_{O_{2} }$ is the partial pressure of oxygen

$P_{50}$ is the partial pressure when 50% hemoglobin is saturated with oxygen

and h is the Hill coefficient

From the question,

${P_{O_{2} }$ = 40 mm Hg

$P_{50}$ = 22 mm Hg

h = 3

Putting these values into the equation, we get

$Y_{O_{2} } = \frac{(P_{O_{2} })^{h} } {(P_{50})^{h} + (P_{O_{2} })^{h} }$

$Y_{O_{2} } = \frac{40^{3} }{22^{3} + 40^{3} }$

$Y_{O_{2} } = \frac{64000 }{10648 + 64000 }$

$Y_{O_{2} } = \frac{64000 }{74648 }$

$Y_{O_{2} } = 0.86$

Hence, the fractional saturation for hemoglobin is 0.86.

4 0

3 years ago