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Describe, in detail, nuclear fission and nuclear fusion. Include what happens in each reaction, the types of atoms involved, the

earnstyle [38]

Answer 1) What is nuclear fission and nuclear fusion?
Nuclear Fission - It is reaction process when a neutron is made to strike to an atom with a heavy nucleus. It makes the atom release certain number of neutrons from the nucleus, then it splits the parent atom into smaller other atoms.

Nuclear Fusion - It is exactly opposite of nuclear fission. It is a reaction process, where the nucleus of certain light atoms tries to join the nucleus of other lighter atoms together and release large amount of energy.

Answer 2) What happens in these reactions?
Nuclear Fission - Usually in these reactions the atoms with heavy nucleus splits up into smaller atoms. Fission means breaking into smaller atoms.

Nuclear Fusion - In this reaction the atoms of several lighter nucleus combines together to form a larger nucleus by releasing a high amount of energy. Fusion means joining/mixing of small atoms to form large atom.

Answer 3) Types of atoms involved?
Nuclear Fission - Atoms with heavy nucleus like uranium which when bombarded with neutrons can get splitted into smaller atoms of xenon or strontium,etc.

Nuclear Fusion - Atoms including small lighter nucleus combines to form larger ones. For example, inside the Sun, the small atoms of hydrogen combines to form helium atoms which imparts sun a large amount of heat and light energy.

Answer 4) Types of product produced?
Nuclear Fission - Depending upon the atoms of heavy nucleus undergoing fission the products would be produced. Such as if uranium undergoes fission the products obtained will be different than Plutonium undergoing fission. Although several small by products may be similar.

Nuclear Fusion - This reaction also depending upon the smaller atoms nucleus which undergoes the process of fusion and result into a bigger atom. Example is the fusion of hydrogen atoms in sun and stars.

Answer 5) Practical Uses.
Nuclear Fission - As in this process large amount of energy is released, the major use is done in producing power. Also it's uses are seen in manufacturing of nuclear weapons.

Nuclear Fusion - It is difficult to do fusion reactions, but still we have managed to manufacture hydrogen bombs using this reaction and many researches are going on in the field of magnetism and laser beams.

Answer 6) Limitations.

Nuclear Fission - The major limitation in using this kind of reaction is because of the generation of radioactive wastes. It is difficult to dispose off the waste generated after the reaction with proper care. It effect remains years after years and are extremely toxic to all living beings.

Nuclear Fusion - It is quite difficult to nuclear fusion reaction on earth as it requires high amount of temperature and pressure. So it is almost impossible to replicate fusion reactions.

3 0

3 years ago

1N2 + 3H2 -->

Hunter-Best [27]

Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

5 0

3 years ago

What is the rate constant of a reaction if rate = 0.2 (mol/L)/s, [A] and [B] are each 3 M, m = 1, and n = 2?

tino4ka555 [31]

M= 1 and n = 2
( m+ n = 1 +2 = 3)

rate = K [A] [B]^2

0.2 = K * 3 * 3 ^2
0.2 = K * 3 * 9
K = 0.2 / 27
K = 7.408 * 10 ^ -3 m^-2 s^-1

4 0

3 years ago

Read 2 more answers

Write the formula for the conjugate base for the following acids. <br>Thank you

Llana [10]

Answer:

See the answer and explanation below , please.

Explanation:

A conjugate base is defined as that formed after an acid donates its proton.

For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:

a) HF + H20 --> F- + H30+

b) H20+ H20 --> OH- + H30+

C)H2PO3- + H20--> HPO3 2- + H30+

d) HSO4- + H20 --> SO4 2- + H30+

E) HCL02 + H20 --> CLO02 - + H30+

7 0

4 years ago

Read 2 more answers

Calculate the percent by mass of carbon in CO2 (carbon dioxide). Please show all work.

anygoal [31]

%C= 12/12 + 2·16=0,273=27,3%.

6 0

3 years ago