Answer:
3.97× 10²³ atoms of Ag
Explanation:
Given data:
Mass of Ni = 112 g
Mass of AgNO₃ = 112 g
Atoms of silver produced = ?
Solution:
Chemical equation:
Ni + 2AgNO₃ → 2Ag + Ni(NO₃)₂
Number of moles of Ni:
Number of moles = mass/ molar mass
Number of moles = 112 g/58.7 g/mol
Number of moles = 2 mol
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 112 g/169.87 g/mol
Number of moles = 0.66 mol
Now we will compare the moles of Ag with both reactants.
AgNO₃ : Ag
2 : 2
0.66 : 0.66
Ni : Ag
1 : 2
2 ; 2×2= 4 mol
Number of moles of Ag produce by AgNO₃ are less so it will limiting reactant and limit the yield of Ag.
I mole = 6.022 × 10²³ atoms
0.66 mol × 6.022 × 10²³ atoms / 1 mol
3.97× 10²³ atoms of Ag
I think the answer should be True! Because the periodic law it states that the physical properties and chemical properties of their elements are periodic into the sequence of their atomic number.
Hope it helped!
⇒ only atom consist of 1 electron and one proton
Rest atoms greater than 1 atomic number (neutral) have neutrons,electrons and protons.