Please answer correctly will give brainlist if correct

PLEASE help me with these questions as soon as possible i need to turn it in!!!!

Sloan [31]

A. I believe this might be the answer but
6 J/60 J= .1
.1 x 100= 10%

b. I'm not sure of this question

19. I'm not sure if I did this correct way or if there is a better way (I'm rusty)
300 J/.50 %= 600
600/100= 6 (answer)

20. (200 J)(.75%) = 150 (answer)
Check:
Efficiency: output/input x 100
150 J/200 J= .75
.75 x 100= 75%

3 0

3 years ago

which relationship best represents the relationship between the magnitude of the centripetal acceleration and the speed of an ob

pashok25 [27]

the object's speed and centripetal acceleration in a circle with a constant radius is the exponential curve going up.

acceleration is the rate of change in both speed and direction of velocity over time. When something moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is constantly shifting, motion on a circle accelerates even when the speed is constant. Both effects add to the acceleration for all other types of motion.

It is a vector quantity because acceleration has both a magnitude and a direction. Another vector quantity is velocity. The velocity vector change over a given period of time, divided by that period of time, is the definition of acceleration. The upper limit of the ratio of velocity change provides instantaneous acceleration (at a specific time and place).

Learn more about acceleration here:

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5 0

1 year ago

Which statement best describes light, whether polarized or unpolarized?

marshall27 [118]

The best choice would be letter C hope this helps

6 0

3 years ago

Read 2 more answers

You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi

Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0

2 years ago

1. Determine the energy released per kilogram of fuel used.

Serga [27]

The formula for energy release per kilogram of fuel burned is energy release per kg=6.702*10-13. and 19. J 1 Mev = 1.602 X 10 T

Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."

Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
19. J 1 Mev = 1.602 X 10 T, which translates to 1.602*1013/2.39x10-3 energy release per kilogram, or 6.702*10-13.

To learn more about Energy please visit -
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8 0

1 year ago