Question

A motor cycle travelling at 10 m/s accelerates at 4m/s for 8s.what is it final velocity? ​

Answer 1

• Initial velocity=u=10m/s
• Acceleration=a=4m/s^2
• Time=t=8s

Final velocity be v

$\\ \bull\tt\longmapsto v=u+at$

$\\ \bull\tt\longmapsto v=10+4(8)$

$\\ \bull\tt\longmapsto v=10+32$

$\\ \bull\tt\longmapsto v=42m/s$

Answer 2

Answer:

• From the first newtons equation of motion:

${ \boxed{ \bf{v = u + at}}}$

v » final velocity which is required.

u » initial velocity, u = 10 m/s

a » acceleration, a = 4 m/s²

t » time, t = 8 seconds

Substitute:

$v = 10 + (4 \times 8) \\ v = 10 + 32 \\ v = 42 \: m {s}^{ - 1} \\ \\ { \underline{ \underline{ \bf{ \: \: final \: velocity = 42 \: m {s}^{ - 1} }}}}$