Answer:
<em> 17.656 m</em>
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Explanation:
Initial speed u = 20 m/s
angle of projection α = 60°
at the top of the trajectory, one fragment has a speed of zero and drops to the ground.
we should note that the<em> top of the trajectory will coincide with halfway the horizontal range of the the projectile travel. This is because the projectile follows an upward arc up till it reaches its maximum height from the ground, before descending down by following a similar arc downwards.</em>
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To find the range of the projectile, we use the equation
R =
where g = acceleration due to gravity = 9.81 m/s^2
Sin 2α = 2 x (sin α) x (cos α)
when α = 60°,
Sin 2α = 2 x sin 60° x cos 60° = 2 x 0.866 x 0.5
Sin 2α = 0.866
therefore,
R = = 35.31 m
<em>since the other fraction with zero velocity drops a top of trajectory, distance between the two fragments assuming level ground and zero air drag, will be 35.31/2 = 17.656 m</em>
The one most common mineral is the feldspar, which takes up 60 % of the weight, and the second most common is quartz. Both have silicon and oxygen in them.
Answer
given,
W = weight of speff at surface of planet = 384 N
h= height = 1.86 x 10⁴ Km
W' = weight of speff at height h from the planet = 24.31 N
Ms = speff mass = 75 kg
M= mass of planet = ?
R = radius of planet
G = 6.67 x 10⁻¹¹ m³/kg.s²
g = 5.187 m/s²
we know,
.......(1)
now,
g' = 0.324 m/s²
.........(2)
dividing equation (1)/(2)
r = 6.2 x 10⁶ m
mass of planet X
from equation 1
M = 3.21 x 10²⁴ kg
If u is about 0.2 (no unit) then the whole left side is zero.