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slavikrds [6]
3 years ago
14

6.

Physics
1 answer:
earnstyle [38]3 years ago
8 0

Answer:

D

Explanation:

the question says "in their related field" so only D makes sense

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Which type of device enables its users to see around corners?
Dmitriy789 [7]

Answer:

We can use optical fibers.

Explanation:

The optical fibers are the optical devices which is based on the total internal reflection.

The optical fiber has two layers, one is called core and the other is called cladding.

The refractive index of core is more than the cladding.

As a ray of light falls on the core at more than the critical angle for that pair of media(core and cladding), it suffers the total internal reflection at the interface.

5 0
4 years ago
Read 2 more answers
Example 4:
earnstyle [38]

Answer:

Given speed of light in diamond =1.24*10m/s

speed of light (c) =3*10^8m/s

refractive index of diamond =3*10^8/1.24*10=2.41*10^7m/s

3 0
3 years ago
Which subatomic particle has a positive charge?
VMariaS [17]
The answer is protons
Electrons have negative charge and neutrons have 0 charge
6 0
4 years ago
Read 2 more answers
single goose sounds a loud warning when an intruder enters the farmyard. Some distance from the goose, you measure the sound lev
Goryan [66]

Answer:

The sound level of the 26 geese is  Z_{26}= 96.15 dB

Explanation:

From the question we are told that

    The  sound level is Z_1 =  81.0 \ dB

     The number of geese is N = 26

Generally the intensity level of sound is mathematically represented as

        The intensity of sound level in dB  for one  goose is mathematically represented as

                       Z_1 = 10 log [\frac{I}{I_O} ]

Where I_o is the  threshold level of intensity with value  I_o = 1*10^{-12} \  W/m^2

            I is the intensity for one goose in W/m^2

For 26 geese the intensity would be  

          I_{26} = 26 * I

   Then  the intensity of 26 geese in dB is  

              Z_{26} = 10 log[\frac{26 I }{I_o} ]

               Z_{26} = 10 log (\ \ 26 *  [\frac{ I }{I_o} ]\ \ )

               Z_{26} = 10 log (\ \ 26  \ \ ) *   (\ \  10 log [\frac{ I }{I_o} ]\ \ )

 From the law of logarithm we have that

              Z_{26} = 10 log 26 +  10 log [\frac{I}{I_0} ]

                    = 14.15 + 82

                    Z_{26}= 96.15 dB

               

               

           

4 0
3 years ago
I need help!!! 60 POINTS!!!!
Scrat [10]
Correct one is b
Good luck
3 0
3 years ago
Read 2 more answers
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