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PilotLPTM [1.2K]

2 years ago

8

If we drop different weights from same height which will fall first to ground? Both of them hit the ground at the same time righ

t?

2 answers:

STALIN [3.7K]2 years ago

7 0

Gravity acceleration is the same so yes, b<span>oth of them hit the ground at the same time.</span>

crimeas [40]2 years ago

5 0

Yes tthey would both hit the ground

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A planet exerts a gravitational force of magnitude 9e22 N on a star. If the planet were 2 times closer to the star (that is, if

Dmitrij [34]

To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

Planet gravitational force

$F_p = 6*10^{22}N$

$F_p = \frac{GMm}{R^2}$

$F_p = 9*10^{22}N$

Distance between planet and star

$r = \frac{R}{2}$

Gravitational force is

$F = \frac{GMm}{r^2}$

Applying the new distance,

$F = \frac{GMm}{(\frac{R}{2})^2}$

$F = 4\frac{GMm}{R^2}$

Replacing with the previous force,

$F = 4F_p$

Replacing our values

$F= 4(9*10^{22}N)$

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3 years ago

If you were to drive an average velocity of 65 mi/hr to Traverse City, which is

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Find the number of hours by dividing the distance by mph. The number of hours will be to the left of the decimal point:

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2) Find the number of minutes by multiplying what is remaining from step 1 by 60 minutes. The minutes will be to the left of the decimal point:

0.846153846 x 60
= 50.76923076
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3) Find the number of seconds by multiplying what is remaining from step 2 by 60 seconds. The seconds will be to the left of the decimal point:

0.76923076 x 60
= 46.1538456
= 46 seconds

So 3 hours 50 mins and 46 seconds

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2 years ago