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Galina-37 [17]
3 years ago
15

Solving Linear Inequalities can someone help me know how to this please

Mathematics
2 answers:
hram777 [196]3 years ago
8 0

Answer:

You solve linear inequalities as if you were solving Linear equation but instend of equals sign there is an inequlitiies sign.

Step-by-step explanation: For example,  2y + 1 ≤ 7

you would subtract 1 on both sides. and then you get 2y=6

then after that you divide 2 on both sides and then you get y<= 6.

I hope this helps!!

KATRIN_1 [288]3 years ago
5 0

Answer:

how to what? I don't understand

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Please help! this is kind of easy
solniwko [45]

Answer:

1st integer=x

2nd integer=x+1

3rd integer=x+2

4th integer=x+3

 

2(x +(x+2))= 3(x+1) +11

 

solve

 

2 (2x +2) = 3x + 3 + 11

 

4x + 4     = 3x + 14

 

-3x-4       =-3x -4

 

 

           x=10

 

1st integer=10

2nd integer=11

3rd integer=12

4th integer=13

Step-by-step explanation:

hopefully this helped

4 0
3 years ago
Read 2 more answers
Sidney has 14 1/2 feet of rope .he cuts off 11 inches from one end . How long is the rope now ?
anygoal [31]

Answer:

short

Step-by-step explanation:

5 0
3 years ago
Please help for brainliest!!!!
mixas84 [53]

Answer:

d)

{i}^{740}

Step-by-step explanation:

i¹= i

i²= -1

i³= -i

i⁴= 1

i¹²⁴= i^(124 +0)

i^124 . i^0

i^(4×31) . i^0 = 1³¹. i^0

1.i^0= i^0

= 1

a) i^179= i^(176+3)

i^176 . i³ = i^(4×44) . i³

1⁴⁴. i³ = 1. i³

= -i

b) i^582 = i^(580 + 2)

i^580 . i²= i^(4×145) . i²

1^145 . i²= 1.i²

= -1

c) i^165= i^(164+1)

i^164 . i¹ = i^(4×41) . i¹

1⁴¹ . i¹ = 1.i

= i

d) i^740= i^(740+0)

i^740 . i^0 = i^(4×185) . i^0

1^185 . i^0 = 1. i^0

= 1

i¹²⁴= i^740 = 1

5 0
3 years ago
The radius of the Morgan family’s circular swimming pool is 8 feet what is the area of the pool cover the Morgan’s use to cover
suter [353]
The working out would be-
Pi x radiussquared
Pi x 64 = 201.0619298297468
Rounded to 2 decimal places =
201.06 feet2
4 0
3 years ago
One year ago
madreJ [45]
\frac{1}{10} * \frac{1{10} * \frac{1}{10} = \frac{1}{1000}
3 0
3 years ago
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