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2 years ago

Solve the inequality below for g.

Mathematics

1 answer:

tiny-mole [99]2 years ago

8 0

Answer:

the answer to the inequality is C. g<1

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I'll give brainlest to first correct answer!!!

zvonat [6]

Answer:

I think there both negative but I'm not sure

Step-by-step explanation:

if one is a positive and one is a negative then reflect over the y axis they should both turn negative

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2 years ago

Kyle drives 330 miles on 15 gallons of gas. How many miles per gallon (mpg) did Kyle get? A) 12 mpg B) 16 mpg C) 19 mpg D) 22 mp

Vikki [24]

Answer:

d. 22mpg

Step-by-step explanation:

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3 years ago

Read 2 more answers

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

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3 years ago

Mr. Kaplan is ordering 30 flash drives for the students in his class if each one cost $11.95 how much will it pay justify your a

kramer

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3 years ago

How much would it cost to fence in this property if fencing costs $5.00 per foot?

stich3 [128]

The answer would be a 1425

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3 years ago