A ball is dropped from the top of an 80 m high building. How long will it take

emmainna [20.7K]

The correct answer is C. more mass and less distance between two objects.

6 0

4 years ago

Which configuration would produce an electric current? A) Rotate a coil of copper wire between two magnets. B) Connect a wire be

FrozenT [24]

the answer is (A) the movement of the magnet relative to the coil

4 0

4 years ago

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A unit for measuring frequency is the <br> A. hertz.<br> B. watt.<br> C. ampere.<br> D. ohm.

Ivahew [28]

One hertz means that an event repeats one per second so the unit for measuring frequency is the hertz and the answer is A.hertz :)))
i hope this be helpful

5 0

3 years ago

Read 2 more answers

Two manned satellites approaching one another at a relative speed of 0.150 m/s intend to dock. The first has a mass of 2.50 ✕ 10

Reika [66]

Answer: $u_{1}=-0.075m/s$ and $u_{2}=0.500m/s$

Explanation:

An elastic collision is one in which both the total kinetic energy of the system and the linear momentum are conserved. That is, during the collision there is no sound, heat or permanent deformations in the bodies as a result of the impact.

Now, in the case of the satellites described here, we have:

$m_{1}v_{1}+m_{2}v_{2}=m_{1}u_{1}+m_{2}u_{2}$ (1) Conservation of momentum

$\frac{1}{2}m_{1}v_{1}^{2} +\frac{1}{2}m_{2}v_{2}^{2} =\frac{1}{2}m_{1}u_{1}^{2} +\frac{1}{2}m_{2}u_{2}^{2}$ (2) Conservation of kinetic energy

Where:

$m_{1}=2.5(10)^{3}kg$ is the mass of the first satellite

$m_{2}=7.5(10)^{3}kg$ is the mass of the second satellite

$v_{1}=0.150m/s$ is the initial velocity of the first satellite

$v_{2}=0m/s$ is the initial velocity of the second satellite (we are told it is at rest)

$u_{1}$ is the final relative velocity of the first satellite

$u_{2}$ is the final relative velocity of the second satellite

Now, as we know the second satellite is at rest before the collision, equations (1) and (2) change to:

$m_{1}v_{1}=m_{1}u_{1}+m_{2}u_{2}$ (3)

$\frac{1}{2}m_{1}v_{1}^{2}=\frac{1}{2}m_{1}u_{1}^{2} +\frac{1}{2}m_{2}u_{2}^{2}$ (4)

Solving this system of equations we have the equations for $u_{1}$ and $u_{2}$ :

$u_{1}=\frac{v_{1}(m_{1}-m_{2})}{m_{1}+m_{2}}$ (5)

$u_{2}=\frac{2m_{1}v_{1}}{m_{1}+m_{2}}$ (6)

Substituting the known values on both equations:

$u_{1}=\frac{0.150m/s(2.5(10)^{3}kg-7.5(10)^{3}kg)}{2.5(10)^{3}kg+7.5(10)^{3}kg}$ (7)

$u_{1}=-0.075m/s$ (8) This is the final relative velocity of the first satellite

$u_{2}=\frac{2(2.5(10)^{3}kg)(0.150m/s)}{2.5(10)^{3}kg+7.5(10)^{3}kg}$ (9)

$u_{2}=0.500m/s$ (10) his is the final relative velocity of the second satellite

7 0

4 years ago

Jill has a mixture of sand and iron fillings. The mass of the mixture is 250 g. Jill uses a magnet to seperate the two substance

mars1129 [50]

The total mass of the mixture is 250g

And the mass of the sand is 150 g

So...

250 - 150 = Mass of iron fillings

100g = Mass of the iron fillings

6 0

3 years ago