What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?
I’m sure it’s called a circuit:)
-- pass the light through a lens
The path of the light is bent (refracted) to a new direction.
-- bounce the light off a shiny surface
The light is sent back (reflected) in the direction from which it arrived.
-- pass the light through a prism
The light is spread out according to the different wavelengths
that may be in it.
-- put something black in the light's path
The light is completely absorbed and is never seen again.
-- turn the light off
The source stops emitting light.
-- throw a towel over the lamp
The light is absorbed in the towel, and not seen outside of it.
The answer is B
As seen on the graph, the bus maintains a 9m/s speed for a majority of the trip to school.
Ans: a = 2.50 m/s^2
Explanation:
First convert the mass in its standard unit i.e. kilogram(kg):
2250 lbs = 1020.583kg
Next use Newton's Second law:
F = ma
Where F = 2552N
m = 1020.583kg
=> a = (2552/1020.583)
a = 2.50 m/s^2
