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2 years ago

I have two questions I need help with.

1 answer:

4 0

1). The Earth would need much much much much much more mass than it has in order to see any change in our orbital period around the sun. An increase of 20% won't jhave any effect.

3). This question isn't clear. "years" isn't a unit of length or distance. It can't describe a change in our distance from the sun, so we don't know what this question is actually asking.

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1. What are valence electrons used for by an element?

jarptica [38.1K]

Answer:

An element's valence electron tells us about its ability to react and not react. More rules to this, but that's the gist of it. it also helps us form bonds

Explanation:

4 0

3 years ago

The work energy principle states that the change in kinetic energy of an object is equal to the net work done on the object. If

sattari [20]

Answer:

$v=\sqrt{2gh}\ m/s$

Explanation:

From work energy theorem

Work done by all forces = Change in kinetic energy

Lets take

m= mass of object

h=height from the ground surface

initial velocity of object = 0 m/s

The final velocity of object is v

Work done by gravitational force = m g . h

The final kinetic energy = 1/2 m v²

Work done by all forces = Change in kinetic energy

m g h = 1/2 m v² - 0

v² = 2 g h

$v=\sqrt{2gh}\ m/s$

6 0

3 years ago

How long will it take a person walking at 3.2 m/s to travel 16 m? *

BigorU [14]

Answer:

speed=distance/time

time=distance/speed

time=16/3.2

time=5 seconds

time will take 5 seconds

3 0

2 years ago

758 j of heat are added to 0.750 kg of copper. how much does its temperature change?(unit=degrees c) PLEASE HELPPPPPPP MEEEEEE

DiKsa [7]

Answer:

$2.6^{\circ}C$

Explanation:

When a substance is supplied with a certain amount of heat energy, the temperature of the substance increases according to the equation

$Q=mC\Delta T$

where

m is the mass of the substance

Q is the amount of energy supplied

C is the specific heat of the substance

$\Delta T$ is the temperature change

In this problem:

Q = 758 J is the energy supplied

m = 0.750 kg is the mass of the sample

$C=385 J/kg^{\circ}C$ is the specific heat of copper

Re-arranging the equation, we can find the increase in temperature:

$\Delta T=\frac{Q}{mC}=\frac{758}{(0.750)(385)}=2.6^{\circ}C$

5 0

3 years ago

What is the speed of electron having the same kinetic energy with photon speed 0.006c?

Blababa [14]

Answer:

if gossipy egg overriding successors spatial

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2 years ago