A. The balanced chemical equation is correct:
k2co3 + 2hcl --> 2kcl + co2 + h2o
B. First let us calculate the moles of K2CO3.
moles K2CO3 = 3 g / (138.205 g/mol) = 0.0217 mol
From the equation, we need 2 moles of HCl per 1 mole of
K2CO3, hence:
moles HCl needed = 0.0217 mol * 2 = 0.0434 mol
So the volume required is:
volume HCl = 0.0434 mol / 6 M = 7.24 x 10^-3 L = 7.24 mL
C. The number of moles of HCl and KCl is equal hence:
moles KCl = 0.0434 mol
The molar mass of KCl is 74.5513 g/mol, so the mass is:
mass KCl = 0.0434 mol * 74.5513 g/mol = 3.24 grams
Order of Solubility of given alcohols is as follow,
Ethanol Butanol Hexanol
Highly Soluble ---------->--------------------->------------------------>---Slightly Soluble
As we know Like dissolves Like. Water is a polar solvent and dissolves readily those compounds which are polar in nature. The solubility of all these alcohols is due o the -OH (hydroxyl) group which tends to form Hydrogen Bond interactions with the water molecules. The difference comes in the alkyl group of these compounds. The akyl group is non polar in nature and immiscible in water. As the non polar chain increases from ethanol to hexanol, so the solubility also decreases from ethanol to hexanol.
Answer:The bowling ball
The lake
The barbell resting on the floor
Explanation:
I got it right on edge
Answer:
On heating sodium hydrogen carbonate (NaHCO3). It decomposes to form sodium carbonate (Na2CO3), water (H2O) and carbon dioxide (CO2)
(ii) 2NaHCO3(s)Heatsodiumcarbonate(sodaash)Na2CO3(s)+CO2(g)+H2O(l)
Answer:
79.4 kg
Explanation:
The formula for potassium iodide is:-
This means that they are present in the same mole ration, i.e. 1 : 1
Also for 2 samples, the ratio of the masses must be equal .
So,
Thus,
Mass of potassium in sample 1 = 13.0 g
Mass of Iodine in sample 1 = 42.3 g
Mass of potassium in sample 2 = 24.4 kg
Applying in the above formula, we get that:-
Mass of iodine in sample 2 = 79.4 kg
