The concentration of acetic acid in the vinegar is found to be 0.5857 M.
<u>Explanation:</u>
Here one mole of acetic acid is used to neutralize one mole of sodium hydroxide. According to the law of Volumetric analysis, we can write the equation as,
V1M1 = V2M2
V1 and M1 being the volume and molarity of NaOH
V2 and M2 being the volume and molarity of CH₃COOH
M2 = 
= 
= 0.5857 M
So the concentration of acetic acid in the vinegar is 0.5857 M.
Answer:
4HCl(g)+O2(g)= 2H2O(g)+2Cl2(g)
∆H=-27.36 kcal
Explanation:
The balanced equation shows that four molecules of HCl reacts with one molecule of Oxygen to give two molecules of water and two molecules of chlorine gas and evolves energy in a combustion reaction.
<span>This is false. A carbohydrate is a carbon-based molecule that can be utilized by living organisms in order to produce energy. A calorie is a unit of energy often used to measure the amount of energy within food. Another example of energy unit is the Joule, more commonly used within physics.</span>
1 — Element D and A ( Which are Sodium and aluminium )
2 — ( 2 + 8 + 3 = 13 electrons total ) Element A Because it's atomic number is 13.
3 — Element E Is stable. ( Which is Argon )
( Note, Elements which has 8 election on its outermost cell is stable. ( Helium is exception which is a noble gas but have 2 electrons in outermost cell )
4 — Element F , which is hydrogen. ( Hydrogen is the only element to not have any neutron )
5 — Element D ( Which is sodium )
6 — The element F ( Which is hydrogen ) Don't contain any neutron.
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We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em> XeF₆</em>
