A vertical angle to tpq could be qpt. We need an image to solve this or a graph.
Answer:
p = k(d)/u^2
Step-by-step explanation:
<em>BRAINLIEST, PLEASE!</em>
Answer:
a = 4
d = a2 - a1
d = 7 - 4
d = 3
an = 43
an = a + (n - 1)d
43 = 4 + (n - 1) 3
43 = 4 + 3n - 3
43 = 1 + 3n
43 - 1 = 3n
3n = 42
n = 42 ÷
n = 14
So, 14th term is 43
Please MARK AS BRAINLIEST
I'm pretty sure they are all correct
