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3 years ago

Solve |2x-4|<8 (Picture added, multiple choice)

Mathematics

2 answers:

natka813 [3]3 years ago

6 0

Answer:

I think its c

Step-by-step explanation:

Trava [24]3 years ago

5 0

Answer:

B. x $\geq$ -2 < and x $\leq$ 6

Step-by-step explanation:

|2x - 4| $\leq$ 8 we need to get rid of brackets and to do that:

-8 $\leq$ 2x - 4 $\leq$ 8 now add 4 to all sides of equation

-4 $\leq$ 2x $\leq$ 12 divide by 2

-2 $\leq$ x $\leq$ 6

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\frac{3}{4} \times 2 =

suter [353]

To multiply two fractions, you simply multiply numerators and denominators together.

2 can be read as the fraction 2/1

So, the multiplication is

$\dfrac{3}{4} \times \dfrac{2}{1} = \dfrac{3\times 2}{4 \times 1} = \dfrac{6}{4} = \dfrac{3}{2}$

8 0

4 years ago

Solve the system of equation by guess sidle method

lilavasa [31]

Answer: The solution is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

Step-by-step explanation:

Given equations are,

$8x_1 + x_2 + x_3 = 8$

$2x_1 + 4x_2 + x_3 = 4$

$x_1 + 3x_2 + 5x_3 = 5$ ,

From the above equations,

$x_1=\frac{1}{8}(8-x_2-x_3)$

$x_2=\frac{1}{4}(4-2x_1-x_3)$

$x_3=\frac{1}{5}(5-x_1-3x_2)$

First approximation,

$x_1(1)=\frac{1}{8}(8-(0)-(0))=1$

$x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5$

$x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5$

Second approximation,

$x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875$

$x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375$

$x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625$

Third approximation,

$x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875$

$x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875$

$x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875$

Fourth approximation,

$x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781$

$x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141$

$x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359$

Fifth approximation,

$x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938$

$x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691$

$x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598$

Hence, by the Gauss Seidel method the solution of the given system is,

$x_1\approx 0.876$

$x_2\approx 0.419$

$x_3\approx 0.574$

4 0

3 years ago

What is an equation of the line that passes through the point

Diano4ka-milaya [45]

Answer:

(y+7)=5/6(x+6)

Step-by-step explanation:

For this problem we need to use Point-Slope Form to write an equation.

We already have the point, (-6,-7), so all we need now is the slope, which we know is perpendicular to the line 6x+5y=30.

First, let's find the slope of 6x+5y=30 by converting it into Slope-Intercept Form, which is y=mx+b. m is the slope.

6x+5y=30

5y=-6x+30

y=-6/5x+6

So the slope of this line is -6/5, but we need the slope of the line is perpendicular to this line.

When a line is perpendicular to another, their slopes are negative reciprocals to one another, or opposite reciprocals. For example, a line that is perpendicular to another line that has a slope of 3/4 will have a slope of -4/3. Flip the numerator and denominator to find the reciprocal and add a negative.

So the negative reciprocal of -6/5 is 5/6, so that is our slope.

Now we can assemble our equation, here is the Point-Slope Form:

$(y -y_{1}) =m(x-x_{1})$