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igomit [66]
3 years ago
6

Which measurement would be different if you were on the Moon versus on Earth? a mass b. weight​

Physics
1 answer:
Aleks04 [339]3 years ago
7 0
The answer is B. weight
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Can the magnitude of a vector ever (a) be equal to one of its components, or (b) be less than one of its components? 9. Can a pa
Ber [7]

Answer:

a) the other components are zero, in the direction of one of the coordinate axes

b) the magnitude is less than the value of one of its components, it must occur when the vector is in some arbitrary direction

9) constant velocity the acceleration must necessarily be zero,

constant speed  can be accelerated since it may be changing the direction of the velocity vector

Explanation:

Vectors are quantities that have modulo (scalar) direction and sense.

a)  If in a vector its magnitude is equal to one d its components implies that the other components are zero, therefore the vector must be in the direction of one of the coordinate axes

b) if the magnitude is less than the value of one of its components, it must occur when the vector is in some arbitrary direction, other than the direction of the axes, that is

          R² = x² + y²

where R is the magnitude of the vector e x, and are the components

9) When a particle has a constant velocity, the acceleration must necessarily be zero,

         v = vo + a t

The bold letters indicate vectors If a = 0 implies that v = vo

If a particle has constant speed it can be accelerated since it may be changing the direction of the velocity vector, this type of acceleration has the name of centripetal acceleration

6 0
3 years ago
Explain the relationship between the distance between the string and your elbow and the effort required to lift the mass.
MissTica

Answer:

Sorry I I’m a little lost

Explanation:

5 0
3 years ago
Read 2 more answers
Please help with this problem ASAP!!!
Alika [10]

Answer:

its point Y because the dot that represents Y is cose to s and can make a chan reaction

3 0
4 years ago
What statement below is true about Mercury?
Evgesh-ka [11]

Answer: It is B 38% have a good day :DDD

4 0
3 years ago
A total charge of –6.50 µC is uniformly distributed within a sphere that has a radius of 0.150 m. What is the magnitude and dire
Marrrta [24]

Answer:

A) 2.89 × 105 N/C, radially inward

Explanation:

The magnitude of the electric field generated by a charged sphere is given by the following formula:

E=k\frac{Q}{r^2}  ( 1 )

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

Q: charge of the sphere = -6.50*10^-6 C

r: distance from the center of the sphere to the point in which E is calculated

r = 0.150m + 0.300m = 0.450 m

You replace the values of Q and r in the equation (1):

E=(8.98*10^9Nm^2/C^2)\frac{6.50*10^{-6}C}{(0.450m)^2}=288246.91\frac{N}{C}\\\\E\approx2.89*10^5\frac{N}{C}

The electric field points radially inward because the charge is negative.

hence, the answer is:

A) 2.89 × 105 N/C, radially inward

7 0
4 years ago
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