Which measurement would be different if you were on the Moon versus on Earth? a mass b. weight

1. An electron in an atom absorbs a photon with an energy of 2.38 eV and jumps from the n = 2 to n = 4 energy level in the atom.

oksian1 [2.3K]

1. $1.0\cdot 10^{-6}m$

First of all, let's convert the energy of the absorbed photon into Joules:

$E=2.38 eV \cdot (1.6\cdot 10^{-19}J/eV)=1.98\cdot 10^{-19} J$

The energy of the photon can be rewritten as:

$E=\frac{hc}{\lambda}$

where

h is the Planck constant

c is the speed of light

$\lambda$ is the wavelength of the photon

Re-arranging the formula, we can solve to find the wavelength of the absorbed photon:

$\lambda=\frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.98\cdot 10^{-19} J}=1.0\cdot 10^{-6}m$

2. 1.24 eV

In this case, when the electron jumps from the n=4 level to the n=3 level, emits a photon with wavelength

$\lambda=1.66\cdot 10^{-6}m$

So the energy of the emitted photon is given by the formula used previously:

$E=\frac{hc}{\lambda}$

and using

$\lambda=1.66\cdot 10^{-6}m$

we find

$E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1.0\cdot 10^{-6}m}=1.99\cdot 10^{-19}J$

converting into electronvolts,

$E=\frac{1.99\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=1.24eV$

EDIT: an issue in Brainly does not allow me to add the last 2 parts of the solution - I have added them as an attachment to this post, check the figure in attachment.

7 0

3 years ago

In the afternoon, Adam rides his bike from his home to the mall to pick up a job application.Then he rides back home to take a n

garri49 [273]

Answer:

The magnitude of Adam's displacement is 0 m

Explanation:

Given;

Adam's distance from his home to the mall, d₁ = 1100m

then, his distance from the mall back to his home, d₂ = 1100m

Adam's displacement is given by;

Displacement = final position - initial position

Adam's displacement = d₂ - d₁

Adam's displacement = 1100 m - 1100 m = 0 m

Therefore, the magnitude of Adam's displacement is 0 m

6 0

4 years ago

If a car has a momentum of 2.04 x 104 kgm/s and a velocity of 18 m/s, what is its mass?

muminat

Answer:

Mass = 1133.33 kg (Approx.)

Explanation:

Given:

Momentum = 2.04 x 10⁴ kg[m/s]

Velocity = 18 m/s

Find:

Mass

Computation:

Mass = Momentum / Velocity

Mass = [2.04 x 10⁴] / 18

Mass = 1133.33 kg (Approx.)

5 0

3 years ago

If a decision was made to increase agriculture fertilizer application, which would be an example of a negative trade-off based o

Murrr4er [49]

The answer is; A

Fertilizer application can be detrimental when there is overapplication. The excess nutrients are washed away by runoff after precipitation. These nutrients end up in water bodies and cause algal blooms. Algal blooms asphyxiate aquatic life hence causing a drastic reduction in aquatic populations.

3 0

3 years ago

Suppose that a 1000 kg car is traveling at 25 m/s (aprox 55mph). Its brakes can apply a force of 5000N. What is the minimum dist

Brrunno [24]

Assuming the the car is travelling to the right (→):

$R(\rightarrow), F = ma$