Answer:
The force exerted by the block on the floor is 38.4 Newtons
Explanation:
The given parameters are;
The area of the box in contact with the floor, A = 2.4 m²
The pressure exerted by the block on the floor, P = 16 N/m²
The force exerted by the box on the floor is given as follows;
∴ F = P × A
From the question, P = 16 N/m², and A = 2.4 m²
∴ F = 16 N/m² × 2.4 m² = 38.4 N
The force exerted by the block on the floor, F = 38.4 N.
Answer:
Displacement is fundamental unit
The answer correct is C:The cell is most likely prokaryotic ,but it could be eukaryotic since some unicellular are eukaryotic.
(a)
KE = m v^2 / 2 = (1200 kg)(20 m/s)^2 / 2 = 240,000 J
(b)
The energy is entirely dissipated by the force of friction in the brake system.
(c)
W = delta KE = KEf - KEi = (0 - 240,000) J = -240,000 J
(d)
Fd = delta KE
F = (delta KE) / d = (-240,000 J) / (50 m) = -4800 N
The magnitude of the friction force is 4800 N.
