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Otrada [13]
3 years ago
12

an airplane traveling 245 m/s east expericences turbulence, so the pilot slows down to 230 m/s. it takes the pilot 7 seconds to

slow down to this speed. what is the acceleration of the plane? round ur answer to the nearest hundredth
Physics
1 answer:
lana66690 [7]3 years ago
8 0

Answer:

a=v-u/t

a=245-230/7

a=2

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Se tienen 500g de alcohol etílico a una temperatura de -40 °C ¿Cuánto calor se necesita para transformarlo a vapor a una tempera
Feliz [49]

The question is: You have 500g of ethyl alcohol at a temperature of -40 ° C. How much heat is needed to transform it into steam at a temperature of 150ºC?

Answer: 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of -40^{o}C to 150^{o}C.

Explanation:

Given: Mass = 500 g

Initial temperature = -40^{o}C

Final temperature = 150^{o}C

The standard value of specific heat of ethyl alcohol is 2.46 J/g ^{o}C.

Formula used to calculate the heat energy is as follows.

q = m \times C \times (T_{2} - T_{1})

where,

q = heat energy

m = mass of substance

C = specific heat

T_{1} = initial temperature

T_{2} = final temperature

Substitute the values into above formula as follows.

q = m \times C \times (T_{2} - T_{1})\\= 500 g \times 2.46 J/g^{o}C \times [150 - (-40)]^{o}C\\= 233700 J

Thus, we can conclude that 233700 J heat is needed to transform ethyl alcohol into steam at a temperature of -40^{o}C to 150^{o}C.

8 0
3 years ago
Using dimensional analysis, construct a constant, with units of length only, out of all three of the following fundamental const
ludmilkaskok [199]

The quantity with units of length only is \sqrt{\frac{hG}{c^3}}

Explanation:

We have to combine the following constants:

- h, Planck constant, with units [m^2][kg][s^{-1}]

- G, the Newton's gravitational constant, with units [m^3][kg^{-1}][s^{-2}]

- c, the speed of light, with units [m][s^{-1}]

The combination of these constant should have units of length only, so with meters (m).

First, we notice that h has [kg] in its units, while G has [kg^{-1}] in its units, so in order to make the [kg] disappear, we have to multiply them and they should have same power, so:

hG = [m^{2+3}][kg^{1-1}][s^{-1-2}]=[m^5][s^{-3}]

Now we have to make the seconds, [s], disappear. We do that by dividing the new quantity by c^3, so that the new units are:

\frac{hG}{c^3}=\frac{[m^5][s^{-3}]}{([m][s^{-1}])^3}=\frac{[m^5][s^{-3}]}{[m^3][s^{-3}]}=[m^2]

We are almost done: now the quantity has units of an area, squared meters. Therefore, in order to make it have it units of length, we just take its square root:

\sqrt{\frac{hG}{c^3}}=\sqrt{[m^2]}=[m]

Learn more about gravitational constant:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

4 0
3 years ago
What is the term for the pattern of spiral impressions inside a handgun?
Korolek [52]
It's called rifling, to stabilise the bullet.
4 0
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5)<br> (64(6-2) =<br> A)<br> 62<br> B)<br> 8-9<br> C)<br> 122<br><br> 12-8
skelet666 [1.2K]

Answer:

B 8-9 because you had to subtract that number or simplify. then your answer is 8-9

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Answer:

I think then answer for this question is number c. the South pole

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