So to solve this question, your goal is to find out how the way it is solved is not correct.
Your answer would be: On the third line, the student adds the 8 to both sides instead of subtracting. The way the initial equation is given is
y-(-8)=-6(x-2). After distributing the six, the student should make the 8 positive because subtracting a negative makes a positive. After solving, the equation should look like: y(+8)=-6x+12, so you would subtract the 8 from both sides instead of adding it, and solve from there.
Answer:

Step-by-step explanation:
So we have the expression:

And we wish to factor it.
First, let's make a substitution. Let's let u be equal to x². Therefore, our expression is now:

This is a technique called quadratic u-substitution. Now, we can factor in this form.
We can use the numbers -3 and -2. So:

For the first two terms, factor out a u.
For the last two terms, factor out a -3. So:

Grouping:

Now, substitute back the x² for u:

And this is the simplest form.
And we're done!
Answer:
At first, we have 3 expressions that are equal.




This is not true.