Ask question

Ask question

All categories

3 years ago

14

One nucleus contains 31 protons and 40 neutrons another nucleus contains 31 protons and 41 neutrons what can you conclude about

the identity of this neclei

2 answers:

Pavel [41]3 years ago

5 0

They are isotopes of the same element.

antiseptic1488 [7]3 years ago

4 0

They are isotopes of the same element

You might be interested in

The pitch of a note corresponds to which property of sound wave

Ksivusya [100]

A high pitch sound corresponds to a high-frequency sound wave and a low pitch sound corresponds to a low-frequency sound wave. So, the pitch of a note corresponds to the amount of frequency of a sound wave. Hope this helped!

8 0

3 years ago

Help<br> A. 12,240<br> B. 6,120

nata0808 [166]

Answer:

A. 12,240.

Explanation:

1,530 times 8.0 = 12,240.

hope this helped :)

3 0

2 years ago

How can someone, like myself, share roughly 50% of their DNA with a 1st Cousin?

iragen [17]

Answer:

that's your 1st cousin which is your mom or dad's sibling's child sooo when you're that close and that related i would say that that would be the reason why.

Explanation:

hoped that helped!!

4 0

3 years ago

The electric field in a certain region of Earth’s atmo- sphere is directed vertically down. At an altitude of 300 m the field ha

I am Lyosha [343]

Answer:

Net charge contained in the cubeq= 3.536×10^-6C

Explanation:

Formular for total flux in a cube is given as:

Total flux= E300Acos(180) + E200Acos(0)

Where A is crossectional area

Total flux= A(E200-E300)

Total flux= q/Eo

q= Eo×total flux

q=(8.84×10^-12)×(100)^2×(100-60)

q= 3.536×10^-6C

6 0

3 years ago

Read 2 more answers

A particle has a charge of +1.5 µC and moves from point A to point B, a distance of 0.15 m. The particle experiences a constant

kirill [66]

Answer:

Part a)

$F = 6 \times 10^{-3} N$

Direction of force is along the motion of charge

Part b)

$E = 4000 N/C$

direction of electric field is along the direction of motion

Explanation:

Part a)

As we know that the change in electric potential energy is equal to the work done by electric field

$W = EPE_A - EPE_B$

$W = 9.0 \times 10^{-4} J$

now from the equation of work done we know that

$W = F.d$

$(9.0 \times 10^{-4}) = F(0.15)$

$F = 6 \times 10^{-3} N$

Direction of force is along the motion of charge

Part b)

As we know the relation between electrostatic force and electric field given as

$F = qE$

$(6 \times 10^{-3}) = 1.5 \times 10^{-6} E$

$E = 4000 N/C$

direction of electric field is along the direction of motion

8 0

2 years ago