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Luden [163]
3 years ago
6

Select the correct answer

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

Step-by-step explanation:

uhh tbh I don not know sorry

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Complete the table for the value of each digit in 123.
artcher [175]

Answer:

1,2,3,4,5,6,7,8,9,10

2,4,6,8,10,12,14,16,18,20

3,6,9,12,15,18,21,24,27,30

Step-by-step explanation:

6 0
3 years ago
Can someone pls help me i don’t get this
Novosadov [1.4K]
V = 60 as the triangle is looking like a equilateral triangle
7 0
3 years ago
Read 2 more answers
Find an angle between 0 and 2pi that is coterminal with the following angle.<br><br> 32pi/9
never [62]
<span>To do these you will be adding or subtracting  2pi (or integer multiples of .

Since the given angles are in fraction form, it will help to have 2pi  in fraction form, 2pi=10/5=6pi/3=4pi/2=18pi/9     NOTE: this>(/) stands for over like 1 over 2 EX. 1/2

too, so the addition/subtraction is easier.

Hint: When deciding if you have a number between 0 and 2pi, compare it to the fraction version of 2pi that you've been adding/subtracting.


For 17pi/5...
First we can see that 17pi/5 is more than 10pi/5 (aka 2pi). So we need to start subtracting: 17pi/5 - 10pi/5 = 7pi/5

Now we have a number between 0 and 10pi/5. So 7pi/5 is the co-terminal angle between 0 and 2pi.

I'll leave the others for you to do. Just remember that you might have to add or subtract  multiple times before you get a number between 0 and 2pi.
P.S don't add or subtract at all if the number starts out between 0 and 2pi.</span>
5 0
3 years ago
CAN SOMEONE HELP PLEASE <br> m4A=42°, b=10, c= 12. What is the length of a to the nearest tenth?
kipiarov [429]

<u>Answer:</u>

a = 8.1

<u>Step-by-step explanation:</u>

Use the cosine rule:

a = \sqrt{b^2 + c^2 -2 bc \space\ cosA }

Substituting the values:

a = \sqrt{10^2 + 12^2 -2(10)(12) \space\ cos 42 \textdegree\ }

⇒ a = \sqrt{4 \space\ cos 42\textdegree\ }

⇒ a = 8.1

4 0
2 years ago
81% passed. What percent did not pass?
Hitman42 [59]
100% - 81% = 19%

19% did not pass.
7 0
3 years ago
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