No, 1/a^b (a^-b) doesn't equal -a^b
A measurement that closely agrees with an accepted value is best described as a numerical
Answer:
Jeremy Will have more than just $200 to spend on Christmas presents.
Explanation :
He has a total of $1200.
He spends a $120 for car insurance. (1)
He needs to spend $25 a week for lunch. He has to do this for 16 weeks so 25*16 = $400. (2)
He needs to spend $20 a week for entertainment. For 16 weeks that'll be 20*16 = $320 (3)
adding (1) (2) and (3)
We get Jeremy's total spending will be $840. Jeremy has $1200.
1200-840 = $360
So Jeremy will have $360 to spend on Christmas present.
Option C
The football team had a overall loss of 2 yards
<em><u>Solution:</u></em>
When the team gains yards we use a positive value, and when the team loses yards we use a negative value.
<em><u>Given that, football team gains 2 yards on the first play</u></em>
First play = +2
<em><u>Given that football team loses 5 yards on the second play</u></em>
Second play = -5
<em><u>Given that football team loses 3 yards on the third play</u></em>
Third play = -3
<em><u>Given that football team gains 4 yards on the fourth play</u></em>
Fourth play = +4
Put the yards from four plays together, we get
⇒ 2 -5 -3 + 4
Let us simplify
⇒ -3 -3 + 4 = -6 + 4 = -2
So, -2 represents loss of two yards (since negative value indicates loss)
F(x+h) = 2(x+h) +3= 2x + 2h +3
f(x) = 2x + 5
f(x+h) - f(x) = 2x + 2h + 3- 2x - 3= 2h
[f(x+h) - f(x)]/h = 2h/h = 2
