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11111nata11111 [884]
3 years ago
10

Solve for x -6x + 14 <-28 OR 9x + 15 < -12

Mathematics
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

1.) x > 7

2.) x < -3

Step-by-step explanation:

1.) -6x + 14 < -28

-14. -14.

______________

-6x. < -42

/-6. /-6

_______________

x > 7 (always flip the sign when dividing by a negative #)

2.) 9x + 15 < -12

-15. -15

______________

9x < -27

/9. /9

_______________

x < -3 (since 9 is not negative, no need to flip the sign)

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Please answer. In parallelogram WXYZ, diagonals WY and XZ intersect at point A. Give WA=x^2-48 and AY=x^2-6x. What is WY? Show y
netineya [11]

The diagonals of a parallelogram are congruent

The length WY is 32

<h3>How to determine the length WY</h3>

Given that:

WA = x^2 - 48 and

AY = x^2 - 6x

Then, we have:

x^2 - 48 = x^2 - 6xdiagonal

Subtract x^2 from both sides

- 48 =- 6x

Divide both sides by -6

x = 8

The length WY is calculated as:

WY=2 * WA

So, we have:

WY=2 * [x^2 - 48]

Substitute 8 for x

WY=2 * [8^2 - 48]

Simplify

WY=32

Hence, the length WY is 32

Read more about parallelograms at:

brainly.com/question/10062747

6 0
2 years ago
Can someone help please?
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Answer:

y=1X

Step-by-step explanation:

This is because the distance over the money made over the days worked is 2/2 which simplifies to 1 so that would be the one x. then the y intercept is found on the y axis where does the line cross the y axis? this would be at zero so you do not need to put that in the equation

8 0
3 years ago
if the exchange rate of euro to the us dollar is 1 euro = $1.13, how much would you receive if you wished to exchange 235 euros?
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It would be $265.55
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What is the value of the expression 4/7 ÷ 12/21
son4ous [18]
Your answer is 1
:::::::::

6 0
3 years ago
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ITO
Setler [38]

Using the speed - distance relationship, the time left before the appointed time is 27 minutes.

<u>Recall</u><u> </u><u>:</u>

  • Distance = speed × time

  • Let time = t

<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>

  • Distance = 10 × (t + 3) = 10t + 30 - - - (1)

<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>

  • Distance = 12 × (t - 2) = 12t - 24 - - - - (2)

<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>

10t + 30 = 12t - 24

<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>

10t - 12t = - 24 - 30

-2t = - 54

<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>

t = 54 / 2

t = 27

Hence, the time left before the appointed time is 27 minutes.

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