Answer:
A box plot is drawn with end points at 24 and 49.The box extends from 28 to 44 and a vertical line is drawn inside the box at 34.
Step-by-step explanation:
Ordering the data given :
24,28,32,34,40,44,49
We can calculate the 5 number summary required to give the appropriate boxplot that can be produced :
Minimum = 24
Maximum = 49
Median = 1/2(n+1)th term
n = 7
Median = 1/2(8) = 4th term
Median = 34
Lower quartile, Q1 = 1/4(n+1)th term
n = 7
1/4(8) = 2nd term
Q1 = 28
Upper quartile : 3/4(n+1)th term
n = 7
Q3 = 3/4(8) = 6th term
Q3= 44
pls mark as brainlist
Step-by-step explanation:
1)70,108,262
2)5,319,602
Answer:
611 square miles
Step-by-step explanation:
Area of triangle = (1/2)*a*b*sinC (formula when u are not given the height of the triangle, but u are given with the angle.)
= (1/2)*30*47*sin(60°)
= 610.54 square miles (2 d.p)
≈611 square miles (rounded to nearest mile)
:)
The first one is wrong
(do you need help solving it?)
Answer:
1. ΔXYZ is a right Δ with altitude YU.
Given
2. ΔXYZ ~ ΔYUZ
Right Triangle Altitude Similarity Theorem
3. VW || XY
Given
4. ∠VWZ ≅ ∠XYZ
Corresponding angles
5. ∠Z ≅ ∠Z
Reflexive property of congruence
6. ΔXYZ ~ ΔVWZ
AA Similarity postulate
7. ΔYUZ ~ ΔVWZ
Transitive property of similar triangles
Step-by-step explanation:
The first statement is given in the problem. Since we know the altitude of a right triangle, we can use the Right Triangle Altitude Similarity Theorem to say that the triangles formed by the altitude are similar to each other and the original triangle.
Next, we are given in the problem statement that the lines VW and XY are parallel. Therefore, ∠VWZ and ∠XYZ are corresponding angles, which makes them congruent. And since ∠Z is equal to itself (by reflexive property), we can use AA similarity to say ΔXYZ and ΔVWZ are similar.
Finally, combining statements 2 and 6, we can use transitive property to say that ΔYUZ and ΔVWZ are similar.
