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JulijaS [17]
3 years ago
10

Pls help me Will mark you as brain plssss

Physics
2 answers:
Ann [662]3 years ago
6 0

Answer:

he can explore other types of physical activity

Explanation:

lifting weights and paddling will help but running could also help

stepan [7]3 years ago
4 0
Activity’s is asum I don’t even know sorry
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Inert gas used to make bright city lights True or False
gogolik [260]

the answer is true because i think its true not 100 percent sure

8 0
3 years ago
PLEASE HELP 15 POINTS The electric field around a positive charge is shown in the diagram. Describe the nature of these lines. P
DENIUS [597]

The field lines spread apart as we move away from the charge, and they point away from the charge

Explanation:

The electric field produced by a single-point positive charge is a radial field, whose strength is given by the equation

E=k\frac{Q}{r^2}

where

k is the Coulomb's constant

Q is the magnitude of the charge

r is the distance from the charge at which the field is calculated

There are two pieces of information given by the field lines shown in the graph:

  • The spacing between the lines gives an indication of the strength of the field: the closer to each other they are, the stronger the field. In this case, as we move away from the charge, the spacing between the lines increases, and this means that the field becomes weaker (in fact, it follows an inverse square law, E\propto \frac{1}{r^2}
  • The direction of the lines gives the direction of the electric field, which points away from the central charge. This is because the  direction of the electric field corresponds to the direction  of the force that a positive test charge would feel when immersed in the electric field: in this case, if we place a positive test charge in this field, then it would get repelled away from the central charge (remember that the electric force between two positive charges is repulsive), and therefore, the direction of the electric field is away from the central charge.

Learn more about electric field:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

8 0
3 years ago
Suppose that a simple pendulum consists of a small 81 g bob at the end of a cord of negligible mass. If the angle θ between the
MariettaO [177]

Answer:

(a) 0.115 m

(b) 2.08 x 10^-5 J

Explanation:

mass of bob, m = 81 g = 0.081 kg

The equation of oscillation is given by

θ = 0.068 Cos {9.2 t + Ф}

Now by comparison

The angular velocity

ω = 9.2 rad/s

(a) \omega^{2} =\frac{g}{L}

where, L be the length of the pendulum

L =\frac{g}{\omega ^{2}}

L =\frac{9.8}{9.2 \times 9.2}

L = 0.115 m

(b) A = L Sinθ

A = 0.115 x Sin 0.068

A = 7.8 x 10^-3 m

Maximum kinetic energy

K = 0.5 x mω²A²

K = 0.5 x 0.081 x 9.2 x 9.2 x 7.8 x 7.8 x 10^-6

K = 2.08 x 10^-5 J

8 0
3 years ago
Helpppppp!!!!
Advocard [28]

Below are the examples of work being done on an object

Carrying a box up a flight of stairs.

Lifting a bag of groceries.

Lifting a rock off the ground.

Pushing a grocery cart through the store.

<h3>Workdone</h3>

Work is said to be done when a force applied moves a distance

Work done = force × distance

Learn more about work done:

brainly.com/question/18762601

5 0
2 years ago
Read 2 more answers
An open-end mercury manometer is connected to a low-pressure pipeline that supplies a gas to a laboratory. Because paint was spi
almond37 [142]

Answer:

A. Using

Pgauge= Pmanometer

And we know that

Pgauge= deta(hpg)

So deta h = Pgauge/density x g

So

= 7.5(6894.76/1psig)/ 13.6*10^3*9.8m/s²)

= 387.9mm

So to find height of pipe connected to the pipe we say

= h -deta h

= 900-387.97mm

=512.02mm

B. We use manometry principle

Pgas+density xg(25*10^3)-PX density{h-(H-0.25)=0

So

Finally Pgas= 6.54psig

3 0
3 years ago
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