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2 years ago

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If Scoobie could drive a Jetson's flying car at a constant speed of 450.0 km/hr across oceans and space, approximately how long

would Scoobie take to drive around Earth's equator in days? Use 6200 km for the radius of the Earth. unanswered

1 answer:

vladimir2022 [97]2 years ago

7 0

Answer:

The value is $t = 3.6 \ days$

Explanation:

From the question we are told that

The speed is $v = 450.0 km/h$

The radius of the earth is $R = 6200 \ km$

Generally the circumfernce of the earth is mathematically evaluated as

$C = 2\pi R$

=> $C = 2 * 3.142 * 6200$

=> $C = 38960.8 \ km$

Generally the time taken is mathematically represented as

$t = \frac{38960.8}{450.0}$

$t = 86.6 \ hr$

Converting to days

$t = \frac{86.6}{24}$

=> $t = 3.6 \ days$

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(a) The force the ground exerts on each set of rear wheels when the plane is at rest on the runway is 0.743 MN.

(b) The force the ground exerts on the front set of wheels is 0.239 MN.

<h3>Center mass of the airplane</h3>

The concept of center mass of an object can be used to dtermine the mass distribution of the airplane along the line through the center.

<h3>Some assumptions</h3>

The wheels under the wind do not pass through the center line.
The position of the front wheel is constant and it is zero mark (origin).
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Position of the center mass of the plane is calculated as follows;

Let the position of the center mass, Xcm = y

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There are two rear wheels, and the force exerted on each wheel due to mass of the airplane at this position is calculated as follows;

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