All categories

3 years ago

Which of the following is numerically the same as the specific gravity? Mass Weight Density Volume

Physics

2 answers:

vichka [17]3 years ago

8 0

<u>Answer:</u> The specific gravity is numerically equal to the density.

<u>Explanation:</u>

Specific gravity is defined as the ratio of the density of a substance to the density of a reference substance, generally taken as water whose density is 1 g/mL.

It is also known as relative density.

The relationship between specific gravity and density of a substance is given as:

$\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}$

Hence, the specific gravity is numerically equal to the density.

max2010maxim [7]3 years ago

4 0

The answer is density

You might be interested in

An airplane is flying at a constant speed in a positive direction. It slows down when it approaches the airport where it's going

guapka [62]

Negative acceleration d. I think

6 0

2 years ago

When the velocity of a mass on a spring is zero, the acceleration is at

Akimi4 [234]

Answer:

A maximum

Explanation:

When displacement is maximum, velocity is Zero and vice versa

When displacement is maximum, acceleration is maximum and when it is zero, acc. Is zero

3 0

2 years ago

An electron that has a velocity with x component 2.6 × 106 m/s and y component 3.2 × 106 m/s moves through a uniform magnetic fi

elena55 [62]

Answer:

a) $\vec F_{B} = 8.766\times 10^{-14}\,T\,k$ , b) $\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

Explanation:

a) The magnetic force experimented by a particle has the following vectorial form:

$\vec F_{B} = q\cdot \vec v \times \vec B$

The charge of the electron is equal to $-1.602\times 10^{-19}\,C$ . Then, cross product can be solved by using determinants:

$\vec F_{B} = \begin{vmatrix}i&j&k\\-4.165\times 10^{-13}\, C\cdot \frac{m}{s} &-5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = 8.766\times 10^{-14}\,T\,k$

b) The charge of the proton is equal to $1.602\times 10^{-19}\,C$ . Then, cross product has the following determinant:

$\vec F_{B} = \begin{vmatrix}i&j&k\\4.165\times 10^{-13}\, C\cdot \frac{m}{s} &5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

8 0

2 years ago

What is the Morgan-Keenan Spectral Classification system?

Angelina_Jolie [31]

Answer: A method of classifying stars by their temperatures and compositions.

Explanation:

4 0

2 years ago

When light passes from water into air, the light bends away from the normal. Question 4 options: True False

kykrilka [37]

Answer:

True

Explanation:

8 0

2 years ago