1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andrey2020 [161]
3 years ago
5

Which activity would help maintain homeostasis during exercise?

Physics
2 answers:
mezya [45]3 years ago
6 0

Answer:

Speeding up the rate if breathing

Explanation:

The more and quicker you breathe, the more oxygen your cells get

Mademuasel [1]3 years ago
5 0
Decreasing heart rate
You might be interested in
A motorcyclist travelling at 30m/s starts to apply his brake when he is 50m from the traffic light that has just turned red .if
Marat540 [252]

Answer:

9m/s²

Explanation:

Given parameters:

Initial velocity  = 30m/s

Final velocity  = 0m/s

Distance traveled  = 50m

Unknown:

Deceleration  = ?

Solution:

To solve this problem, we apply the proper motion equation;

          V²   = U²   +  2aS

V is the final velocity

U is the initial velocity

a is the acceleration

S is the distance

  Insert the parameters and solve;

          0²  = 30²  + 2(a)50

          -900  = 100a  

              a = -9m/s²

The negative value indicates deceleration.

The motorcycle decelerates at a rate of 9m/s²

3 0
3 years ago
Two objects are raised off the ground and one of them is three times as high as the other one. How do their potential energy com
DochEvi [55]

The potential energy of any object depends on its mass as well as its height off the ground.

Potential energy = mass x gravity x height.

We don't have enough information to compare the potential energies of these two objects because we don't know their masses.

3 0
4 years ago
A child swings a tennis ball attached to a 0.626-m string in a horizontal circle above his head at a rate of 4.50 rev/s.
mr_godi [17]

Explanation:

Length of a string, l = 0.626 m

A tennis ball revolves in a horizontal circle above his head at a rate of 4.50 rev/s.

(a) The centripetal acceleration of the tennis ball is given by :

a=\omega^2r\\\\a=(4.5\times 2\pi)^2\times 0.626\\\\=500.44\ m/s^2

(b) When r = 0.626 m and ω = 4.50 rev/s

Speed,

v=r\omega\\\\=0.626\times 4.50 \times 2\pi\\\\=17.69\ m/s

When r = 1 m and ω = 4 rev/s

Speed,

v=r\omega\\\\=1\times 4 \times 2\pi\\\\=25.13\ m/s

Speed is more in second case when child now increases the length of the string to 1.00m but has to decrease the rate of rotation to 4.00 rev/s.

(c) a=\omega^2r\\\\a=(4\times 2\pi)^2\times 1\\\\=631.65\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
A student throws a set of keys vertically upward to his fraternity brother, who is in a window 4.00 m above. the brother’s outst
guapka [62]
<span>a) 10.0 m/s b) -4.7 m/s The formula for distance under constant acceleration is d = 0.5AT^2 The formula for distance with a specified velocity is d = VT So the distance the keys travel with an initial velocity and under constant acceleration by gravity is d = VT - 0.5AT^2 The acceleration due to gravity is 9.8 m/s^2 and the time T is 1.50 s, and finally, the distance traveled is 4.00 m. So substitute those values into the equation and solve for V d = VT - 0.5AT^2 4.00m = 1.50s * V - 0.5 * 9.8 m/s^2 * (1.5s)^2 Do the multiplications 4.00m = 1.50s * V - 4.9m/s^2 * 2.25 s^2 Cancel the s^2 terms 4.00m = 1.50s * V - 4.9m * 2.25 Do the multiplication 4.00m = 1.50s * V - 11.025m Add 11.025m to both sides 15.025m = 1.50s * V Divide both sides by 1.50s 10.01667 m/s = V Since we have 3 significant figures in the data, round results to 3 significant figures. V = 10.0 m/s So the keys were initially thrown upwards with a velocity of 10.0 m/s Since it took 1.50 seconds from launch to catch, the velocity of the keys will decrease by 9.8 m/s^2 times the time. So V = 10.0 m/s - 1.50s * 9.8 m/s^2 V = 10.0 m/s - 14.7 m/s V = -4.7 m/s So at the time the keys were caught, they were moving downward at a velocity of 4.7 m/s</span>
5 0
3 years ago
An object initially at rest accelerates at 5 meters per second2 until it attains a speed of 30 meters per second. What distance
Ipatiy [6.2K]

Answer:

Distance s  = 90 meter

Explanation:

Given:

Initial velocity u = 0 m/s

Final velocity v = 30 m/s

Acceleration a = 5 m/s²

Find:

Distance s

Computation:

v² = u² + 2as

30² = 0² + 2(5)(s)

Distance s  = 90 meter

5 0
3 years ago
Other questions:
  • Drivers a and b travel west from boston. driver a leaves three hours earlier traveling at a constant speed of 68mph. driver b fo
    15·1 answer
  • A bus accelerates at -0.5 m/s2 for 12.5 seconds . If the bus had an initial speed of 31 m/s, what is its new speed? A. 12.25m/s
    12·1 answer
  • how can you use the periodic table to determine the average number of neutrons in element has even though the number of neutrons
    5·1 answer
  • Why might a food processing company employ a team of scientists? A) to manage the day-to-day running of the company
    12·1 answer
  • Briefly discuss:
    5·1 answer
  • How are metals produced? Does this process use sustainable methods? Explain
    15·1 answer
  • Two identical2,000-kg cars travel each at 50.0 km/h in directions perpendicular to one another. The cars crash and form asingle
    11·1 answer
  • What radiation gets through the atmosphere?
    15·2 answers
  • How much force is needed to accelerate a 2500 kg car at a rate of 4m/s²?
    13·2 answers
  • What’s better csp or pv ?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!