An electric heater that carries a current of 13.5 A when operating at a voltage of 120V , will have the resistance of the heater as 8.89 ohm.
<h3>What is Ohm's law?</h3>
Ohm's law can be described as the law in physics that focus on how voltage or potential difference between two points is directly proportional to the current or electricity that is moving in the direction of the resistance.
An this is also directly proportional to the resistance of the circuit, hence it can be calculated using the Ohm's law is V=IR.
from V=IR
R=V/I
= 120/13.55
=8.89 ohm.
Therefore, electric heater that carries a current of 13.5 A when operating at a voltage of 120V , will have the resistance of the heater as 8.89 ohm.
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Answer:
sure if its easy im jp ill help u
Explanation:
Answer:
energy is equal to 1000 J
Explanation:
When the jumper is in the tent, he has a given height, this height gives him a gravitational potential energy, which forms his initial mechanical energy of 1000 J. After jumping, this energy is converted into elastic energy of the rope plus a remainder of potential energy gravitational, it does not reach the ground, but as the friction is negligible the total mechanical energy is conserved, therefore its energy is equal to 1000 J
This is a case of energy transformation, but the total value of mechanical energy does not change
Given:
Gasoline pumping rate, R = 5.64 x 10⁻² kg/s
Density of gasoline, D = 735 kg/m³
Radius of fuel line, r = 3.43 x 10⁻³ m
Calculate the cross sectional area of the fuel line.
A = πr² = π(3.43 x 10⁻³ m)² = 3.6961 x 10⁻⁵ m²
Let v = speed of pumping the gasoline, m/s
Then the mass flow rate is
M = AvD = (3.6961 x 10⁻⁵ m²)*(v m/s)*(735 kg/m³) = 0.027166v kg/s
The gasoline pumping rate is given as 5.64 x 10⁻² kg/s, therefore
0.027166v = 0.0564
v = 2.076 m/s
Answer: 2.076 m/s
The gasoline moves through the fuel line at 2.076 m/s.
