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N76 [4]
4 years ago
10

An instrument is defective for all of the following conditions EXCEPT:_______

Physics
1 answer:
NARA [144]4 years ago
6 0

Answer:

I believe its C

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A projectile is fired vertically from earth's surface with an initial speed of 5.3 km/s. neglecting air drag, how far above the
MaRussiya [10]
It will rise, and then fall back to the Earth’s surface.
6 0
3 years ago
A drowsy cat spots a flower pot that sails first up and then down past an open window. The pot was in view for a total of 0.56 s
liberstina [14]

Answer:

h = 0.028 m

Explanation:

As we know that

d = \frac{v_2 + v_1}{2} t

here we have

1.95 = \frac{v_2 + v_1}{2}(0.56)

v_2 + v_1 = 6.96

also we know

v_2 - v_1 = at

v_2 - v_1 = (9.81)(0.56)

v_2 - v_1 = 5.49

so we have

v_2 = 6.23 m/s

v_1 = 0.74 m/s

so the height above window is given as

v_f^2 - v_i^2 = 2 a d

0.74^2 - 0 = 2(9.81)h

h = 0.028 m

4 0
3 years ago
-What is the storm on Saturn called?
Harrizon [31]

Answer:

-the Great White Spot

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-Viewed from Earth, Saturn has an overall hazy yellow-brown appearance. The surface that is seen through telescopes and in spacecraft images is actually a complex of cloud layers decorated by many small-scale features, such as red, brown, and white spots, bands, eddies, and vortices, that vary over a fairly short time.

-hexagon

-58,232 km

-0d 10h 42m

-Saturn's hexagon is a persistent approximately hexagonal cloud pattern around the north pole of the planet Saturn, located at about 78°N.

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<h2>Hope it helps...</h2><h2>Have a great day : )</h2>

7 0
3 years ago
Use the crisscross method to find the chemical formula for the ionic compound formed by strontium (Sr) and bromine (Br).​
nignag [31]

Answer:it’s c SrBr2

Explanation:

8 0
3 years ago
Read 2 more answers
A 10.0 cm object is 5.0 cm from a concave mirror that has a focal length of 12 cm. What is the distance between the image and th
fiasKO [112]
Let's use the mirror equation to solve the problem:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where f is the focal length of the mirror, d_o the distance of the object from the mirror, and d_i the distance of the image from the mirror.
For a concave mirror, for the sign convention f is considered to be positive. So we can solve the equation for d_i by using the numbers given in the text of the problem:
\frac{1}{12 cm}= \frac{1}{5 cm}+ \frac{1}{d_i}
\frac{1}{d_i}= -\frac{7}{60 cm}
d_i = -8.6 cm
Where the negative sign means that the image is virtual, so it is located behind the mirror, at 8.6 cm from the center of the mirror.
6 0
3 years ago
Read 2 more answers
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