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2 years ago

2.3 The diameter of a circle is 8 m long. Calculate its: radius

Mathematics

2 answers:

slavikrds [6]2 years ago

4 0

Answer:

Step-by-step explanation:

Diameter is equal to 2r

so,

8÷2=4

xxMikexx [17]2 years ago

4 0

Answer:

Step-by-step explanation:

diameter is 2 times greater than radius

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Please help me with the below question.

tresset_1 [31]

We have the following three conclusions about the piecewise function evaluated at x = 14.75:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

<h3>How to determinate the limit in a piecewise function</h3>

In a piecewise function, the limit for a given value exists when the two lateral limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.

According to the definition of lateral limit and by observing carefully the figure, we have the following conclusions:

$\lim_{t \to 14.75^{-}} f(t) = 66$ .
$\lim_{t \to 14.75^{+}} f(t) = 10$ .
$\lim_{t \to 14.75} f(t)$ does not exist as $\lim_{t \to 14.75^{-}} f(t) \ne \lim_{t \to 14.75^{+}} f(t)$ .

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

8 0

1 year ago

Johnny delivers a 40 $ ring to Michelle s friend . Johnny bring s Michelle the$40 Michelle gives Johnny a $40 ring back how much

Alekssandra [29.7K]

$0. She got the $40 ring and then gave it back. 40-40=0.

7 0

3 years ago

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If a production line produces 50 mouse traps every 30 minutes over the course of a 10 hour work day with a half-hour break for l

stira [4]

The awnser is 1000 because 60 miutes in an hour, 50 mouse traps every half hour so 100 mouse traps an hour multiply that by 10 and you get 1000, i think.

4 0

3 years ago

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Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

5 months ago

Which ordered pair is the solution to the system of equations?

Tcecarenko [31]

The best way to answer this item is to use the Substitution method. Substitute the value of y from the first equation to the y of the second equation such that the second equation becomes,

-4x + 3(x - 4) = -3

Simplifying the equation,
-x = 9

Dividing both sides by -1 gives an answer of,
x = -9

Then, substitute the value of x in the first equation.
y = -9 - 4
 y = -13

The answer to this item is letter B.

6 0

2 years ago

Read 2 more answers