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Molodets [167]
2 years ago
9

What is the relative size of microwaves​

Chemistry
1 answer:
sleet_krkn [62]2 years ago
6 0

Answer:

width of between 29 and 30 inches, a depth of between 15 and 16 inches, and a height of between 16 and 18 inches.

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What are the advantages and disadvantages of fission?
viktelen [127]

<u>Advantages of Nuclear Fission</u>

  • Nuclear fission provides cheapest energy . Almost 10% of electricity used in the world is obtained from the fission reaction
  • It offers a low-emission energy solution since there is no carbon dioxide gas emitted during the  nuclear fission reaction
  • A well controlled and maintained nuclear reactor can produce energy for 36 to 40 months so works for .
  • It is a reliable source of energy as energy is obtained from uranium which is available is plenty.
  • It provides very concentrations of energy as it can provide large amount of energy from small amount of fuel.
  • The reaction gives less annual mortality rate of any energy resource with 90 deaths per trillion kilowatt hours

<u>Disadvantages of Nuclear Fission </u>

  • It is dangerous and  also explosive.
  • It creates harmful and radioactive waste products.
  • It is not a renewable energy resource like solar and wind energy
  • It can develop long-term health issues for people exposed to then radioactive waves.
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5 0
3 years ago
Which is a chemical property of soda ash? A.It's a highly basic substance. B.It's a white crystalline powder. It can dissolve in
LenaWriter [7]
A) its a highly basic substance
5 0
3 years ago
Read 2 more answers
A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

5 0
3 years ago
Element X has two isotopes. If 72.0% of the element has an isotope mass of 84.9 atomic mass units, and 28.0% of the element has
bija089 [108]
<h2>Answer:</h2>

Average atomic mass of an element is the sum of the masses of its isotopes each multiplied by its natural abundance

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ \sum\limits \: \% age \: of \: each \: isotope \times Atomic  \: mass }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 72 \times84.9 + 28 \times 87  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 6112.8 + 2436  }{100} \\

\footnotesize \longrightarrow \:  \rm Average \:  atomic  \: mass =  \dfrac{ 8548.8  }{100} \\

\footnotesize \longrightarrow \:  \bf Average \:  atomic  \: mass =  85.488 \: amu  \\

8 0
2 years ago
When the fuel mixture contained in a 1.49 l tank, stored at 750 mmhg and 298 k, undergoes complete combustion, how much heat is
Ket [755]
Get to know first how many moles in the gas:n = pV/RT= (1.013*10^5*750/760) Pa *1.49*10^-3 m^3/(8.314 J/(molK)*298) n = 0.0601 moles. 
The combustion energies  are  889 kJ/mol (methane) and 2 220 kJ (propane) x = moles methane, y = moles propane 
x*889 + y*2220 = 778 x + y = 0.0601----------- x = 0.267784 moles = 0.267784*100/0.0601 = 44.6 % y = 0.243216 moles = 0.243216*100/0.0601 = 55.4 %
4 0
3 years ago
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