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8090 [49]
3 years ago
5

What is the molarity of a solution of 14.0 g NH4Br in enough H2O to make 150 mL of solution?

Chemistry
2 answers:
kiruha [24]3 years ago
8 0
The molarity of a solution equals to the mole number of the solute/the volume of the solution. For NH4Br, we know that the mole mass is 98. So the molarity is (14/98) mol /0.15 L=0.95 mol/L.
aniked [119]3 years ago
4 0

Explanation:

Molarity is defined as the number of moles per liter of solution.

Mathematically,         Molarity = \frac{no. of moles}{volume of solution in liter}

Since it is given that the molarity of a solution of 14.0 g and volume is 150 mL or 0.15 L.

Whereas number of moles = \frac{mass}{molar mass}

So, molar mass of NH_{4}Br is 97.94 g/mol.

Thus,      number of moles = \frac{14.0 g}{97.94 g/mol}

                                            = 0.142 mol

Therefore, calculate the molarity as follows.

              Molarity = \frac{no. of moles}{volume of solution in liter}  

                             = \frac{0.142 mole}{0.15 L}

                              = 0.946 mol/L

Hence, we can conclude that molarity of the solution is 0.946 mol/L.

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Manganese dioxide (MnO2(s), Hf = –520.0 kJ) reacts with aluminum to form aluminum oxide (AI2O3(s), Hf = –1699.8 kJ/mol) and mang
Temka [501]

Answer : The enthalpy of the reaction = -1839.6 KJ

Solution : Given,

\Delta (H_{f})_{MnO_{2}} = -520.0 KJ/mole

\Delta (H_{f})_{Al_{2}O_{3}} = -1699.8 KJ/mole

The balanced chemical reaction is,

3MnO_{2}(s)+4Al(s)\rightarrow 2Al_{2}O_{3}(s)+3Mn(s)

Formula used :

\Delta (H_{f})_{reaction}=\sum n(\Delta H_{f})_{product}-\sum n(\Delta H_{f})_{reactant}

\Delta (H_{f})_{reaction}=(2\times \Delta H_{Al_{2}O_{3}(s)}+3\times \Delta H_{Mn(s)} )-(3\times \Delta H_{MnO_{2}(s) }+4\times\Delta H_{Al}(s))

We know that the standard enthalpy of formation of the element is equal to Zero.

Therefore, the enthalpy of formation of (Mn) and (Al) is equal to zero.

Now, put all the values in above formula, we get

\Delta (H_{f})_{reaction}=[2moles\times (-1699.8 KJ/mole)}+3moles\times (0\text{ KJ/mole}})]-[(3moles\times(-520.0KJ/mole }+4moles\times(0\text{ KJ/mole})]

                        = (-3399.6) + (1560)

                        = -1839.6 KJ



5 0
3 years ago
Hydrogen gas (H2) reacts with oxygen gas (O2) and produces water. If one mol of hydrogen reacts with one mole of oxygen, what is
Amiraneli [1.4K]
HI 

So, the formula for water is H2O

When you have the same amount of the reactants , hydrogen will be the limiting reactant. 
Limiting reactant is the thing that runs out first.
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3 years ago
The concentration of a solution can be expressed in
puteri [66]
The concentration of a solution can be expressed in (4) <span>moles per liter~</span>
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3 years ago
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Answer:

The Mole-Volume Relationship: Avogadro's Law. A plot of the effect of temperature on the volume of a gas at constant pressure shows that the volume of a gas is directly proportional to the number of moles of that gas. This is stated as Avogadro's law.

Explanation:

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3 years ago
QUESTION 2
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Answer:

A

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