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3 years ago

Whta gasses are in Neptune?

1 answer:

6 0

Neptune's atmosphere is composed up of many gases. These gases include Hydrogen (80%), Helium (19%), and Methane (1.5%). Some of the minor gases include trace amounts of Hydrogen Deuteride and Ethane.

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What is the pH of a 8.7 x 10^-12 M OH- solution ? pH= ?

vivado [14]

PH=14-pOH

pOH=-lg[OH⁻]

pH=14+lg[OH⁻]

pH=14+lg(8.7*10⁻¹²)=14-11.06=2,94

5 0

3 years ago

Read 2 more answers

How much sucrose (g) do you need to weight in order to prepare 19.16 g of a 13.1 % (weight percent) solution?

Nonamiya [84]

2.51 grams
You want to prepare 19.16 g of some solution which will have 13.1% of it's mass being sucrose. So we just need to perform some simple multiplication: 19.16g * 0.131 = 2.50996g
Rounding to 3 significant figures gives 2.51 g.

3 0

3 years ago

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8

Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is $pK_a =7.82$

Explanation:

From the question we are told

The volume of base is $V_B = 26.mL = 0.0260L$

The pH of solution is $pH = 7.82$

The concentration of the acid is $C_A = 0.1M$

From the pH we can see that the titration is between a strong base and a weak acid

Let assume that the the volume of acid is $V_A = 18mL= 0.018L$

Generally the concentration of base

$C_B = \frac{C_AV_A}{C_B}$

Substituting value

$C_B = \frac{0.1 * 0.01800}{0.0260}$

$C_B= 0.0692M$

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

$HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}$

Now before the reaction the number of mole of base is

$No \ of \ moles[N_B] = C_B * V_B$

Substituting value

$N_B = 0.01300 * 0.0692$

$= 0.0009 \ moles$

Now before the reaction the number of mole of acid is

$No \ of \ moles = C_B * V_B$

Substituting value

$N_A = 0.01800 *0.1$

$= 0.001800 \ moles$

Now after the reaction the number of moles of base is zero i.e has been used up

this mathematically represented as

$N_B ' = N_B - N_B = 0$

The number of moles of acid is

$N_A ' = N_A - N_B$

$= 0.0009\ moles$

The pH of this reaction can be mathematically represented as

$pH = pK_a + log \frac{[base]}{[acid]}$

Substituting values

$7.82 = pK_a +log \frac{0.0009}{0.0009}$

$pK_a =7.82$

8 0

2 years ago

Explain heat transfer in your own words

timofeeve [1]

Answer: thermal conductivity

Explanation:

8 0

3 years ago

Come up with 2 examples of each law motion below: 1st law: 2nd law: 3rd law:

Sloan [31]

1st law: Inertia, If you roll a ball it will not stop unless something blocks it by force.

2nd law: Force and Acceleration, when you’re riding a bike you are pushing the pedal with ur muscle which means you’re using force. Everytime you push the pedal the bike goes faster and faster which explains acceleration.

3rd law: Action and Reaction, If you run you’re feet pushes the ground (action) when your feet touches the ground it pushes you forward (reaction)

5 0

2 years ago