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stiks02 [169]
2 years ago
6

3. Two fans blow at 5 ms^-1 in a easterly direction and 8ms^-1 in a Northerly

Physics
1 answer:
Anvisha [2.4K]2 years ago
3 0

Addition of vectors is done by adding the components of the vectors

The total speed of the fan  is approximately <u>9.43 m/s</u>,

Direction of total wind 58° counterclockwise from the positive x-axis

<u />

The reason the value is correct is as follows:

The given parameters are:

The direction at which the fan blowing at 5 m/s is blowing = Easterly

The direction in which the fan blowing 8 m/s is blowing = Northerly

The total speed of the van, |v| ≈ <u>9.43 m/s</u>

<u />

Required:

To find the total wind speed of the fans

Solution:

Taken the easterly direction as the ith component, and the northerly direction as the jth component,  the vector representing the speed of the fan is presented as follows

v = 5·i + 8·j

The magnitude of the total wind speed of the fan, |v| = √(5² + 8²) = √(89) ≈ 9.43

The total wind speed of the fan , |v| ≈ <u>9.43 m/s</u>

The direction of the total speed with respect to the x-axis, θ, is given as follows;

θ = arctan(8/5) ≈ <u>58°</u>

<u />

Learn more about addition of vectors here:

brainly.com/question/17691926

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gizmo_the_mogwai [7]

Answer:

Part a)

P = 13.93 kW

Part b)

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Explanation:

Part A)

heat required to melt the aluminium is given by

Q = ms\Delta T + mL

here we have

Q = 40(950)(680 - 32) + 40(450 \times 10^3)

Q = 24624 kJ + 18000 kJ

Q = 42624 kJ

Since this is the amount of aluminium per hour

so power required to melt is given by

P = \frac{Q}{t}

P = \frac{42624}{3600} kW

P = 11.84 kW

Since the efficiency is 85% so actual power required will be

P = \frac{11.84}{0.85} = 13.93 kW

Part B)

Total energy consumed by the furnace for 30 hours

Energy = power \times time

Energy = 13.93 kW\times 30 h

Energy = 417.9 kWh

now the total cost of energy consumption is given as

R = P \times 20 \frac{Cents}{kWh}

R = 417.9 kWh\times  20 \frac{cents}{kWh}

R = 8357.6 Cents

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3 years ago
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Answer:

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