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Musya8 [376]
3 years ago
11

Which term describes an educated guess about the outcome of an

Physics
2 answers:
bezimeni [28]3 years ago
5 0

Answer:

Hypothesis

Explanation:

Refer to a trial solution to a problem as a hypothesis, often called an "educated guess" because it provides a suggested outcome based on the evidence.

irinina [24]3 years ago
4 0
Hypothesis best describes an educated guess about the outcome of an experiment.
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What supports a white dwarf against the crush of gravity?
weqwewe [10]

Answer:  In particular, electron degeneracy pressure is what supports white dwarfs against gravitational collapse, and the Chandrasekhar limit (the maximum mass a white dwarf can attain) arises naturally due to the physics of electron degeneracy.

Explanation:

5 0
3 years ago
What is t = 0 s and t = 8 s? ​
Deffense [45]

Answer:

t=0 is t

t=8= 8t

Explanation:

because 0 is means "nothing" so that's why t=0 is t

7 0
3 years ago
Help with this question.....​
mariarad [96]

Answer:

g_{moon}=1.67 [m/s^{2} ]

Explanation:

The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.

w =m*g\\

where:

w = weight [N]

m = mass = 0.06 [kg]

g = gravity acceleration = 10 [N/kg]

Therefore:

w=0.06*10\\w=0.6[N]

By Hooke's law we know that the force in a spring can be calculated by means of the following expression.

F=W\\F = k*x

where:

k = spring constant [N/m]

x = deformed distance = 6 [cm] = 0.06 [m]

We can find the spring constant.

k= F/x\\k=0.6/0.06\\k=10 [N/m]

Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.

F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N]

Since this force is equal to the weight, we can now determine the gravitational acceleration.

F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ]

6 0
3 years ago
A normal blood pressure reading is less than 120/80 where both numbers are gauge pressures measured in millimeters of mercury (m
KIM [24]

The pressure value is given by the equation,

P= \rho gh

Where,

\rho represents the density of the liquid

g= gravity

h= Heigth

A) For the measurement of the guage pressure we have the data data,

\rho_{mercury} = 13.6*10^3kg/m^3

h=0.0930m

g=9.8m/s^2

Replacing we get,

P_g=\rho_{mercury}gh

[tex]P_g = (13.6*10^3)(9.8)(0.0930)P_g = 12395Pa[/tex]

In order to find the Absolute pressure, we perform a sum between the atmospheric pressure and that of the Gauge,

B) The atmospheric pressure at sea level is 101325Pa, assuming ideal conditions, we will take this pressure for our calculation, so

P_T = P_a+P_g\\P_T = 101325Pa+12395Pa\\P_T = 113720Pa\\P_T = 113.7kPa

6 0
3 years ago
Charged particles posses a region of influence also called a (an)
Delvig [45]

Answer:(c)

Explanation:

Charge particle posses a region of influence called a filed i.e. Electric field.

It is a region around the charged particle such that other charge particle experiences force due to this field. The nature of force is decided by the charge on the particle creating an electric field.

For a positive charge, electric field lines emerge out of it, and for a negative charge, it acts as radially inwards.

6 0
3 years ago
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