Reduce the rate of global warming
Answer:
150m
Explanation:
The relation of speed/time and distance/time is a derivative/integral one, as in speed is the derivative of distance (the faster you go, the faster the distance changes, duh!).
So we need to compute the integral of speed over time from 0.0s to 5.0s.
The easiest way here is to compute the area under the line (it's going to be faster than computing the acceleration and using a formula of distance based on acceleration).
The area under the line is a trapezoid with "height" 5s, and the bases 10m/s and 50m/s. Using the trapezoid area formula of h*(a + b)/2
distance = 5s * (10m/s + 50m/s) / 2 = 5s * 60m/s / 2 = 5s * 30m/s = 150m
Alternatively, we can use the acceleration formula:
a = (50m/s - 10m/s)/5s = 40m/s / 5s = 8m/s^2
distance = v0 * t + a * t^2 / 2 = 10m/s * 5s + 8m/s^2 * (5s)^2 / 2 = 50m + 8m * 25 / 2 = 50m + 100m = 150m.
Most of the of water in our planet can be found in our oceans, and it is able to absorb most of the "carbon" in our atmosphere. Gases that contain carbon move between ocean's surface and the atmosphere through a process called "diffusion"
Answer
given,
mass of full back, M = 100 Kg
velocity of full back in east = 3.5 m/s
mass of the defensive back,m = 80 Kg
velocity of defensive back, due east = 6 m/s
a) initial momentum of each player
for full back
P₁ = M v = 100 x 3.5 = 350 kg.m/s
for defensive back
P₂= m v = 80 x 6 = 480 kg.m/s
b) total momentum before collision
P = P₁ + P₂
taking west direction as positive
P = 350 + (- 480 )
P = -130 kg.m/s
c) speed of the them when they stick together.
using conservation of momentum
initial momentum = final momentum
-130 = (M + m ) V
180 V = -130
V = -0.722 m/s
velocity after the collision is equal to 0.722 m/s in direction of east.