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Diano4ka-milaya [45]
3 years ago
7

What is the symbol for neutrons

Chemistry
1 answer:
german3 years ago
7 0

Answer:

There are 3 symbols for neutrons.

Explanation:

n , n 0 , N 0

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Which of the following prefixes would be best to use when measuring the distance from your home to the store?
Shalnov [3]
I would say the most correct answer is Kilo, as in kilometers. The store would certainly not be milli, or millimeters away from you, would it now? :)

Hope this helps!
4 0
3 years ago
What did the early atomic theory
Virty [35]

Answer:B

Explanation:

The early theory says that atom Is the smallest indivisible particle. Which was later proven to contain electron neutron and proton

7 0
3 years ago
Read 2 more answers
PLEASE HELP!! 10 POINTS!<br> what could the fourth quantum number of a 2s^2 electron be?
mrs_skeptik [129]

Answer:

D. ms=+1/2.

Explanation:

Hello there!

In this case, since the quantum numbers are known as:

* Principal quantum number (n) which cannot be zero. The allowed values of n are therefore 1, 2, 3, 4, and so on.

* Angular quantum number (l) is able to be any integer between 0 and n-1. If n = 2, for example, l can be either 0 or 1.

* Magnetic quantum number (m) is able to be any integer between -l and +l. If l = 3, m can be either -3, -2, -1, 0, +1, +2 or +3.

* Spin Quantum Number (ms): ms = +½ or -½. Accounts for the orientation of the spin axis of an electron as it is able to spin in only one of two directions.

Thus, since the fourth quantum number is ms, spin, we infer that the answer is D. ms=+1/2 because it represents the positive spin on 2s^2.

Best regards!

5 0
3 years ago
Read 2 more answers
Draw and name the structures of the carboxylic acids and esters you put together using molecular models.
Neporo4naja [7]

Answer:

This question is incomplete

Explanation:

However, when the carboxylic acids and esters put together are obtained, the procedure below can be followed in drawing and naming them.

For carboxylic acid,

1) it should be noted that the functional group here is -COOH which is drawn as -C = OH

      |

     OH

2) The carbon of the functional group is included among the carbon to be counted when naming the structure. For example, the compound below is propanoic acid.

CH₃CH₂COOH - As you can see that there are 3 carbons linked chain there.

3) As can be seen in (2) above, the suffix "oic" is used to name carboxylic acids

4) The carbon chain here is saturated (meaning there is no double or triple bond within the carbon chain)

Example of a structure of carboxylic acid is

H₃C - CH₂ - CH₂ - C = OH

                              |

                             OH

The structure above is a butanoic acid

For ester

1)The functional group here is -COO- . which can be drawn as

- C = O

   |

  O -

(meaning one oxygen atom is double bonded to the carbon and the other oxygen atom is bonded to another carbon chain)

2) The alkyl group attached to the oxygen atom is first of all mentioned before the carbon chain attached from the left is mentioned. For example, CH₃CH₂CH₂COOCH₂CH₃ is ethyl butanoate

3) As seen from (2) above, the suffix "oate" is used to end the name of esters

4) As also seen from (2) above, the carbon of the functional group is also included while counting the carbon chain of the parent name (butanoate).

5) The carbon chains here are also saturated.

Example of this ester is

CH₃CH₂C = O

              |

             O - CH₂CH₃

The name of this compound is ethyl propanoate

3 0
3 years ago
What is the empirical formula of a compound composed of 3.25% hydrogen ( H ), 19.36% carbon ( C ), and 77.39% oxygen ( O ) by ma
lys-0071 [83]

Answer:

The answer to your question is C₂HO₃

Explanation:

Data

Hydrogen = 3.25%

Carbon = 19.36%

Oxygen = 77.39%

Process

1.- Write the percent as grams

Hydrogen = 3.25 g

Carbon = 19.36 g

Oxygen = 77.39 g

2.- Convert the grams to moles

                     1 g of H ----------------- 1 mol

                   3,25 g of H -------------  x

                     x = (3.25 x 1) / 1

                     x = 3.25 moles

                    12 g of C ---------------- 1 mol

                     19.36 g of C ----------  x

                     x = (19.36 x 1) / 12

                     x = 1.61 moles

                     16g of O --------------- 1 mol

                     77.39 g of O ---------  x

                      x = (77.39 x 1)/16

                      x = 4.83

3.- Divide by the lowest number of moles

Carbon = 3.25/1.61 = 2

Hydrogen = 1.61/1.61 = 1

Oxygen = 4.83/1.61 = 3

4.- Write the empirical formula

                        C₂HO₃

5 0
3 years ago
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