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krek1111 [17]
3 years ago
6

A total of 729 students participate in a school pep rally event. If every 30 minutes, 2/3 of the students leave, after 2 hours,

how many students will be still staying at the pep rally?
Mathematics
1 answer:
trapecia [35]3 years ago
5 0

There will be 9 students left at the prep rally after 2 hours.

After 30 minutes

  • Total Number of students = 729
  • 2/3 of 729 = 486
  • Number of students left = 729 - 486 = 243

After 1 hour:

  • 2/3 of 243 = 162
  • Number of students left = 243 - 162 = 81

After 1 hour 30 minutes :

  • 2/3 of 81 = 54
  • Number of students left = 81 - 54 = 27

After 2 hours :

  • 2/3 of 27 = 18
  • Number of students left = 27 - 18 = 9

Therefore, the Number of students left after 2 hours will be 9.

Learn more : brainly.com/question/18112348

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divide both sides by 3

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For the first question, simply make a right angle triangle with the following dimensions.

The angle of elevation or the angle from the ground between the first floor and ground is 60 degrees.

The height between the 2 floors is 26 feet.

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Then for the second question, divide the length in feet by the rate to find the time it takes for the object to move.



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Read 2 more answers
Ariel swims 2 1/6 miles in every 1/3 hour. Enter the number of miles Ariel swims in 1 minute.
weqwewe [10]

In order to find the distance covered in 1 minute, we need to divide distance covered 2 1/6 miles by 20 minutes.We are given : Ariel swims 2 1/6 miles in every 1/3 hour.

Let us convert 1/3 hour into minutes.

There are 60 minutes in an hour.

Therefore, 1/3 hours = 60 × 1/3 = 20 minutes.

So, we could say, "Ariel swims 2 1/6 miles in every 20 minutes".


2 1/6÷ 20 = 13/6 ÷ 20.

Let us convert division sign into multiplication and flip 20 to 1/20.

We get

<h3>13/6 × 1/20 = 13/120 miles in 1 minute.</h3><h3>In decimal 0.11 mile in 1 minute.</h3>
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3 years ago
The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation
Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

  • Sample size: n = 20
  • Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}    

This gives

P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}

P(x = 11) = 0.0011

Express as percentage

P(x = 11) = 0.11\%

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all  20 would graduate? </h3>

Using the binomial probability formula, we have:

P(X = x) = ^nC_x p^x(1 - p)^{n -x}

So, the equation becomes

P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}    

This gives

P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0

P(x = 20) = 0.0388

Express as percentage

P(x = 20) = 3.88\%

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

\mu = np

So, we have:

\mu = 20 \times 85\%

\mu = 17

The standard deviation is calculated as:

\sigma = np(1 - p)

So, we have:

\sigma = 20 \times 85\% \times (1 - 85\%)

\sigma = 20 \times 0.85 \times 0.15

\sigma = 2.55

Hence, the mean and the standard deviation are 17 and 2.55, respectively.

Read more about probabilities at:

brainly.com/question/15246027

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