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Pepsi [2]
2 years ago
12

What is the slope of a line perpendicular to the line whose equation is x - y = -3.

Mathematics
1 answer:
Scorpion4ik [409]2 years ago
6 0

Answer:

m2 = - 1

Step-by-step explanation:

Subtract x  from both sides of the equation

-y = - x - 3      

Divide by - 1

-y/-1 = -x/-1 - 3/-1

y = x + 3

The slope of the line we were given is 1. The 1 is in front of the x

m1 * m2 = - 1

m1 = 1

1*m2 = - 1

m2 = - 1

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Q(x)=x^3+ax^2+2b is divided by (x-3) and has a remainder of 4. Find the values of "a" and "b"​
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Answer:

Let p(x) = x3 + ax2 + bx +6

(x-2) is a factor of the polynomial x3 + ax2 + b x +6

p(2) = 0                                                                                      

p(2) = 23 + a.22 + b.2 +6 =8+4a+2b+6 =14+ 4a+ 2b = 0

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b = - 7 -2a -(i)                                                                              

x3 + ax2 + bx +6 when divided by (x-3) leaves remainder 3.

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11+3a +b =1 => 3a+b =-10 => b= -10-3a -(ii)                                    

Equating the value of b from (ii) and (i) , we have

(- 7 -2a) = (-10 - 3a)

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b = - 7 -2(-3) = -7 + 6 = -1

Thus the values of a and b are -3 and -1 respectively.

Step-by-step explanation:

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(2,3) is your answer

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