Answer:
38 cm from q1(right)
Explanation:
Given, q1 = 3q2 , r = 60cm = 0.6 m
Let that point be situated at a distance of 'x' m from q1.
Electric field must be same from both sides to be in equilibrium(where EF is 0).
=> k q1/x² = k q2/(0.6 - x)²
=> q1(0.6 - x)² = q2(x)²
=> 3q2(0.6 - x)² = q2(x)²
=> 3(0.6 - x)² = x²
=> √3(0.6 - x) = ± x
=> 0.6√3 = x(1 + √3)
=> 1.03/2.73 = x
≈ 0.38 m = 38 cm = x
Answer:
I think it would be a chemical change.
Explanation:
Because a physical would be like crushing it or something along that line.
Answer:
lymph nodes
tonsils and adenoids
thymus
Explanation:
-Arteries are the blood vessels that take the blood that contains oxygen from the heart to the tissues and are part of the circulatory system.
-Lymph nodes are glands that take care of filtering the fluid that goes through the lympathic system and are also important for the functioning of the immune system.
-Capillaries are blood vessels that connect the veins and arteries and are part of the circulatory system.
-Tonsils and adenoids are located in the throat and they help protect the body from diseases and they are part of immune system and the lympathic system.
-Veins are the vessels that take the blood to the heart and they are part of the circulatory system.
-Thymus is an organ in which the T cells develop and they help protect the body against virus and bacteria and it is part of the immune and lympathic systems.
According to this, cells or organs that are considered to be part of both the immune and lymphatic systems are:
lymph nodes
tonsils and adenoids
thymus
Total distance covered = 384 Km
Total time taken to travel from A to B = 8 hours [from 8 am to 4 pm, there are 8 hours]
We know, Average speed = Total Distance Travelled/ Total Time Taken
Therefore, average speed = 384 Km/8 h = 384000m/8×60×60s =(384000/28800)m/s
= 13.3 m/s
Answer is 13.3 m/s
Answer:
Wavelength of the sound wave that reaches your ear is 1.15 m
Explanation:
The speed of the wave in string is
where T= 200 N is tension in the string , 
=1.0 g/m is the linear mass density
Wavelength of the wave in the string is
The frequency is
The required wavelength pf the sound wave that reaches the ear is( take velocity of air v=344 m/s)
