Am I right? Please help!

Calculate the energy of a photon having a wavelength in thefollowing ranges.(a) microwave, with λ = 50.00 cmeV(b) visible, with

IgorLugansk [536]

(a) $2.5\cdot 10^{-6}eV$

The energy of a photon is given by:

$E=\frac{hc}{\lambda}$

where

$h=6.63\cdot 10^{-34}Js$ is the Planck constant

$c=3\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

For the microwave photon,

$\lambda=50.00 cm = 0.50 m$

So the energy is

$E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{0.50 m}=4.0\cdot 10^{-25} J$

And converting into electronvolts,

$E=\frac{4.0\cdot 10^{-25}J}{1.6\cdot 10^{-19} J/eV}=2.5\cdot 10^{-6}eV$

(b) $2.5 eV$

For the energy of the photon, we can use the same formula:

$E=\frac{hc}{\lambda}$

For the visible light photon,

$\lambda=500 nm = 5 \cdot 10^{-7}m$

So the energy is

$E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-7} m}=4.0\cdot 10^{-19} J$

And converting into electronvolts,

$E=\frac{4.0\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=2.5 eV$

(c) $2500 eV$

For the energy of the photon, we can use the same formula:

$E=\frac{hc}{\lambda}$

For the x-ray photon,

$\lambda=0.5 nm = 5 \cdot 10^{-10}m$

So the energy is

$E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{5\cdot 10^{-10} m}=4.0\cdot 10^{-16} J$

And converting into electronvolts,

$E=\frac{4.0\cdot 10^{-16}J}{1.6\cdot 10^{-19} J/eV}=2500 eV$

6 0

3 years ago

What type of simple machine is an electric fan?

GrogVix [38]

Answer:

An electric fan is considered to be a mixture of several simple machines. It includes the Wheel and Axle type, wedges, and the Inclined plane types. The blades of an electric fan are the inclined planes and the wedges.

5 0

3 years ago

Which type of material uses the subtractive coloring process?

Triss [41]

I think that the answer is A

6 0

3 years ago

What will happen to the centripetal acceleration if the velocity of the object increases to two times its original value?

mrs_skeptik [129]

Answer:

<em>the centripetal acceleration will now be four times its initial value</em>

Explanation:

v=velocity

a=centripetal acceleration

r=radius to the center

take note tat a centripetal force is the force tat is needed to keep a body moving along a circular path

centripetal force is given by f=mv^2/r

a=v^2/r

v=v $v_{0}$

wen v $v_{0}$ is doubled , we ave

2v $v_{0}$

substituting into the previous equation of centripetal force

a=( $(2v_{0})^{2}$ /r

a=4 $v_{0}$ ^{2}/(r)

from the equation, is can be discovered that the centripetal acceleration will now be four times its initial value

4 0

4 years ago

A car travels at a constant speed of 30km/h for .80h what is the total distance

Simora [160]

Answer:

2400 km

Explanation:

30km for 1hr

Need up to 80 hrs , multiply both 80 and 30

So its 2400km

4 0

3 years ago